按键和返回父键的PHP多维数组搜索[重复]

This question already has an answer here:

这个问题在这里已有答案：

Retrieve all parent keys of a given child key in Array 1 answer
在Array 1 answer中检索给定子键的所有父键

I have array which looks like this:

我有这样的数组：

$array = array(
    53 => array(
        'name' => 'category',
        'subcats' => array(
            42 => array(
                'name' => 'subcategory',
            ),
            152 => array(
                'name' => 'subcategory',
                'subcats' => array(
                    431 => array(
                        'name' => 'subsubcategory'
                    )
                )
            )
        )
    ),
    94 => array(
        'name' => 'category'
    ),
    12 => array(
        'name' => 'category',
        'subcats' => array(
            67 => array(
                'name' => 'subcategory',
            ),
            237 => array(
                'name' => 'subcategory',
            ),
            109 => array(
                'name' => 'subcategory',
            ),
            32 => array(
                'name' => 'subcategory',
        )
    )
);

As you can see keys are numbers, but those are IDs of categories which can be infinitely nested into each other. What I need is to search this array for specific ID and return array of it and its parents. We can safely assume that keys would not duplicate even in subcategories array - they are IDs from MySQL AI field;

正如您所看到的，键是数字，但这些是类别的ID，可以无限地嵌套在一起。我需要的是在这个数组中搜索特定的ID并返回它的数组及其父节点。我们可以放心地假设即使在子类别数组中键也不会重复 - 它们是来自MySQL AI字段的ID;

So the expected result for searching key 431 would be:

因此，搜索关键字431的预期结果将是：

array(53, 152, 431);

Any help would be appreciated, I just can't wrap my head around this ;)

任何帮助将不胜感激，我只是无法绕过这个;）

2 个解决方案

#1

This works -

这工作 -

function find_id_list($array, $key){
    if(in_array($key,array_keys($array))){
        return Array($key);
    }
    foreach($array as $k=>$v){
        if(in_array("subcats",array_keys($v))){
            $result = find_id_list($v["subcats"], $key);
            if ($result !== null){
                array_unshift($result,$k);
                return $result;
            }
        }
    }
    return null;
}

OUTPUT:

OUTPUT：

$val = find_id_list($array, 431);
var_dump($val);
/*  OUTPUT
    array
      0 => int 53
      1 => int 152
      2 => int 431
*/

$val = find_id_list($array, 109);
var_dump($val);
/*  OUTPUT
    array
      0 => int 12
      1 => int 109
*/

$val = find_id_list($array, 0);
var_dump($val);
/*  OUTPUT
    null
*/

#2

You can use a recursive function to solve this issue.

您可以使用递归函数来解决此问题。

function searchmulti($arr, $num)
{
    if (!isset($arr[$num])) {
        foreach ($arr as $key => $subarr)
        {
            if (isset($subarr['subcats']))
            {
                $ret = searchmulti($subarr['subcats'], $num);
                if ($ret)
                {
                    $ret[] = $key;
                    return $ret;
                }
            }
        }
    } else return array($num);
    return null;
}

$solution = array_reverse(searchmulti($array,431));

Output

产量

$solution => array(53,152,431);

$ solution => array（53,152,431）;

#1