I have .jpg file in my folder and its sub folders.
我的文件夹及其子文件夹中有.jpg文件。
image/1/large/imagexyz.jpg
image/1/medium/imageabc.jpg
image/1/small/imagedef.jpg
and so on for 2,3,4 ...
等2,3,4 ......
I need to rename all image files with its folder name. ie. imagexyz.jpg should be large_1.jpg and imageabc.jpg should be medium_1.jpg and so on.
我需要用其文件夹名称重命名所有图像文件。即。 imagexyz.jpg应该是large_1.jpg，imageabc.jpg应该是medium_1.jpg等等。
4 个解决方案
#1
3
oldIFS="$IFS"
IFS=/
while read -r -d $'\0' pathname; do
# expect pathname to look like "image/1/large/file.name.jpg"
set -- $pathname
mv "$pathname" "$(dirname "$pathname")/${3}_${2}.jpg"
done < <(find . -name \*.jpg -print0)
IFS="$oldIFS"
#2
3
#!/bin/sh
find . -type f -name "*.$1" > list
while read line
do
echo $line
first=`echo $line | awk -F/ '{print $2}'`
echo $first
second=`echo $line | awk -F/ '{print $3}'`
echo $second
name=`echo $line | awk -F/ '{print $4}'`
echo $name
mv "./$first/$second/$name" ./$first/$second/${first}_${second}.$1
done < list
If you save this file as rename.sh then run rename.sh jpg to replace jpg files and rename.sh png to replace png and so on.
如果将此文件另存为rename.sh，则运行rename.sh jpg以替换jpg文件，并运行rename.sh png以替换png，依此类推。
#3
2
A solution based upon native bash functions (well, except find, then ;-) )
基于本机bash函数的解决方案（好吧，除了查找，然后;-)）
#!/bin/bash
files=`find . -type f -name *.jpg`
for f in $files
do
echo
echo $f
# convert f to an array
IFS='/'
a=($f)
unset IFS
# now, the folder containing a digit
# are @ index [2]
# small, medium, large are @ [3]
# and name of file @ [4]
echo ${a[2]} ${a[3]} ${a[4]}
echo ${a[3]}_${a[2]}.jpg
done
#4
1
Did you mean something like that?
你的意思是那样的吗？
for i in $(find image/ -type f); do
mv $i $(echo $i | sed -r 's#image/([0-9]+)/([^/]+)/[^/]+.jpg#\2_\1.jpg#');
done
This will move all files from image/$number/$size/$file.jpg to ./${size}_${number}.jpg.
这会将所有文件从image / $ number / $ size / $ file.jpg移动到./${size}_${number}.jpg。
But be aware that you will overwrite your files if there is more than one .jpg file in each image/$number/$size directory (see comment of kurumi).
但请注意，如果每个图像/ $ number / $ size目录中有多个.jpg文件，则会覆盖您的文件（请参阅kurumi的评论）。
#1
3
oldIFS="$IFS"
IFS=/
while read -r -d $'\0' pathname; do
# expect pathname to look like "image/1/large/file.name.jpg"
set -- $pathname
mv "$pathname" "$(dirname "$pathname")/${3}_${2}.jpg"
done < <(find . -name \*.jpg -print0)
IFS="$oldIFS"
#2
3
#!/bin/sh
find . -type f -name "*.$1" > list
while read line
do
echo $line
first=`echo $line | awk -F/ '{print $2}'`
echo $first
second=`echo $line | awk -F/ '{print $3}'`
echo $second
name=`echo $line | awk -F/ '{print $4}'`
echo $name
mv "./$first/$second/$name" ./$first/$second/${first}_${second}.$1
done < list
If you save this file as rename.sh then run rename.sh jpg to replace jpg files and rename.sh png to replace png and so on.
如果将此文件另存为rename.sh，则运行rename.sh jpg以替换jpg文件，并运行rename.sh png以替换png，依此类推。
#3
2
A solution based upon native bash functions (well, except find, then ;-) )
基于本机bash函数的解决方案（好吧，除了查找，然后;-)）
#!/bin/bash
files=`find . -type f -name *.jpg`
for f in $files
do
echo
echo $f
# convert f to an array
IFS='/'
a=($f)
unset IFS
# now, the folder containing a digit
# are @ index [2]
# small, medium, large are @ [3]
# and name of file @ [4]
echo ${a[2]} ${a[3]} ${a[4]}
echo ${a[3]}_${a[2]}.jpg
done
#4
1
Did you mean something like that?
你的意思是那样的吗？
for i in $(find image/ -type f); do
mv $i $(echo $i | sed -r 's#image/([0-9]+)/([^/]+)/[^/]+.jpg#\2_\1.jpg#');
done
This will move all files from image/$number/$size/$file.jpg to ./${size}_${number}.jpg.
这会将所有文件从image / $ number / $ size / $ file.jpg移动到./${size}_${number}.jpg。
But be aware that you will overwrite your files if there is more than one .jpg file in each image/$number/$size directory (see comment of kurumi).
但请注意，如果每个图像/ $ number / $ size目录中有多个.jpg文件，则会覆盖您的文件（请参阅kurumi的评论）。