I am trying to download a zip file from my web api controller. It is returning the file but I am getting a message the zipfile is invalid when i try to open. I have seen other posts about this and the response was adding the responseType: 'arraybuffer'. Still isn't working for me. I'm not getting any errors in the console either.
我想从我的web api控制器下载一个zip文件。它正在返回文件但我收到一条消息,当我尝试打开时,zipfile无效。我已经看过其他关于此的帖子,响应是添加了responseType:'arraybuffer'。仍然不适合我。我也没有在控制台中出现任何错误。
var model = $scope.selection;
var res = $http.post('/api/apiZipPipeLine/', model)
res.success(function (response, status, headers, config) {
saveAs(new Blob([response], { type: "application/octet-stream", responseType: 'arraybuffer' }), 'reports.zip');
notificationFactory.success();
});
api controller
api控制器
[HttpPost]
[ActionName("ZipFileAction")]
public HttpResponseMessage ZipFiles([FromBody]int[] id)
{
if (id == null)
{//Required IDs were not provided
throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.BadRequest));
}
List<Document> documents = new List<Document>();
using (var context = new ApplicationDbContext())
{
foreach (int NextDocument in id)
{
Document document = context.Documents.Find(NextDocument);
if (document == null)
{
throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.NotFound));
}
documents.Add(document);
}
var streamContent = new PushStreamContent((outputStream, httpContext, transportContent) =>
{
try
{
using (var zipFile = new ZipFile())
{
foreach (var d in documents)
{
var dt = d.DocumentDate.ToString("y").Replace('/', '-').Replace(':', '-');
string fileName = String.Format("{0}-{1}-{2}.pdf", dt, d.PipeName, d.LocationAb);
zipFile.AddEntry(fileName, d.DocumentUrl);
}
zipFile.Save(outputStream); //Null Reference Exception
}
}
finally
{
outputStream.Close();
}
});
streamContent.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
streamContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment");
streamContent.Headers.ContentDisposition.FileName = "reports.zip";
var response = new HttpResponseMessage(HttpStatusCode.OK)
{
Content = streamContent
};
return response;
}
}
Update
更新
2 个解决方案
#1
15
I think you're setting the responseType in the wrong place, instead of this:
我认为你将responseType设置在错误的位置,而不是:
$http.post('/api/apiZipPipeLine/', model)
Try this:
尝试这个:
$http.post('/api/apiZipPipeLine/', model, {responseType:'arraybuffer'})
Take a look at this answer for more details.
请查看此答案以获取更多详细信息。
#2
3
At a matter of fact you are rigth adding responseType:'arraybuffer'
. That added to the following code when received the response from ajax will prompt a file to download:
事实上,你正在添加responseType:'arraybuffer'。当收到来自ajax的响应时,添加到以下代码将提示下载文件:
var a = document.createElement('a');
var blob = new Blob([responseData], {'type':"application/octet-stream"});
a.href = URL.createObjectURL(blob);
a.download = "filename.zip";
a.click();
#1
15
I think you're setting the responseType in the wrong place, instead of this:
我认为你将responseType设置在错误的位置,而不是:
$http.post('/api/apiZipPipeLine/', model)
Try this:
尝试这个:
$http.post('/api/apiZipPipeLine/', model, {responseType:'arraybuffer'})
Take a look at this answer for more details.
请查看此答案以获取更多详细信息。
#2
3
At a matter of fact you are rigth adding responseType:'arraybuffer'
. That added to the following code when received the response from ajax will prompt a file to download:
事实上,你正在添加responseType:'arraybuffer'。当收到来自ajax的响应时,添加到以下代码将提示下载文件:
var a = document.createElement('a');
var blob = new Blob([responseData], {'type':"application/octet-stream"});
a.href = URL.createObjectURL(blob);
a.download = "filename.zip";
a.click();