下载在Flask中即时生成的文件的首选方法

I have a page that displays a list of files in a directory. When the user clicks on the Download button, all of these files are zipped into a single file, which is then offered for download. I know how to send this file to the browser when the button is clicked, and I know how to reload the current page (or redirect to a different one), but is it possible to do both in the same step? Or would it make more sense to redirect to a different page with a download link?

我有一个页面,显示目录中的文件列表。当用户单击“下载”按钮时,所有这些文件都压缩为单个文件,然后提供下载。我知道如何在单击按钮时将此文件发送到浏览器,并且我知道如何重新加载当前页面(或重定向到另一个页面),但是是否可以在同一步骤中执行这两个操作?或者通过下载链接重定向到不同的页面会更有意义吗?

My download is initiated with the Flask API's send_from_directory. Relevant test code:

我的下载是使用Flask API的send_from_directory启动的。相关测试代码:

@app.route('/download', methods=['GET','POST'])
def download():
    error=None
    # ...

    if request.method == 'POST':
        if download_list == None or len(download_list) < 1:
            error = 'No files to download'
        else:
            timestamp = dt.now().strftime('%Y%m%d:%H%M%S')
            zfname = 'reports-' + str(timestamp) + '.zip'
            zf = zipfile.ZipFile(downloaddir + zfname, 'a')
            for f in download_list:
                zf.write(downloaddir + f, f)
            zf.close()

            # TODO: remove zipped files, move zip to archive

            return send_from_directory(downloaddir, zfname, as_attachment=True)

    return render_template('download.html', error=error, download_list=download_list)

Update: As a workaround, I am now loading a new page with the button click, which lets the user initiate the download (using send_from_directory) before returning to the updated listing.

更新:作为一种解决方法,我现在正在加载一个单击按钮的新页面,这允许用户在返回更新列表之前启动下载(使用send_from_directory)。

1 个解决方案

#1

Are you running the flask app behind a front end web server such as nginx or apache (which would be the best way to handle the downloading of files). If you're using nginx you can use the 'X-Accel-Redirect' header. For this example I'll use the directory /srv/static/reports as the directory you're creating the zipfiles in and wanting to serve them out of.

您是否在前端Web服务器(如nginx或apache)后面运行烧瓶应用程序(这将是处理文件下载的最佳方式)。如果您使用的是nginx,则可以使用“X-Accel-Redirect”标题。对于这个例子,我将使用目录/ srv / static / reports作为你正在创建zipfiles的目录,并希望将它们提供给它们。

nginx.conf

in the server section

在服务器部分

server {
  # add this to your current server config
  location /reports/ {
    internal;
    root /srv/static;
  }
}

your flask method

你的烧瓶方法

send the header to nginx to server

将标头发送到nginx到服务器

from flask import make_response
@app.route('/download', methods=['GET','POST'])
def download():
    error=None
    # ..
    if request.method == 'POST':
      if download_list == None or len(download_list) < 1:
          error = 'No files to download'
          return render_template('download.html', error=error, download_list=download_list)
      else:
          timestamp = dt.now().strftime('%Y%m%d:%H%M%S')
          zfname = 'reports-' + str(timestamp) + '.zip'
          zf = zipfile.ZipFile(downloaddir + zfname, 'a')
          for f in download_list:
              zf.write(downloaddir + f, f)
          zf.close()

          # TODO: remove zipped files, move zip to archive

          # tell nginx to server the file and where to find it
          response = make_response()
          response.headers['Cache-Control'] = 'no-cache'
          response.headers['Content-Type'] = 'application/zip'
          response.headers['X-Accel-Redirect'] = '/reports/' + zf.filename
          return response

If you're using apache, you can use their sendfile directive http://httpd.apache.org/docs/2.0/mod/core.html#enablesendfile

如果你正在使用apache,你可以使用他们的sendfile指令http://httpd.apache.org/docs/2.0/mod/core.html#enablesendfile

#1