用正则表达式捕获查询字符串的值?

I am trying to select just what comes after name= and before the & in :

我试着选择name=后面和& in之前的内容:

"/pages/new?name=J&return_url=/page/new"

So far I have..

到目前为止我有. .

^name=(.*?).

I am trying to return in this case, just the J, but its dynamic so it could very several characters, letters, or numbers.

在这种情况下，我试图返回J，但是它是动态的，所以它可以有很多字符，字母，或数字。

The end case situation would be allowing myself to do a replace statement on this dynamic variable found by regex.

最终情况是允许我对regex找到的这个动态变量执行替换语句。

6 个解决方案

#1

/name=([^&]*)/

/ name =(^ & *)/

• remove the ^ and end with an &
• 删除与一个& ^和结束

---

Example:

例子:

var str     = "/pages/new?name=J&return_url=/page/new";
var matches = str.match(/name=([^&]*)/);
alert(matches[1]);

---

The better way is to break all the params down (Example using current address):

更好的方法是打破所有的参数(例如使用当前地址):

function getParams (str) {
   var queryString = str || window.location.search || '';
   var keyValPairs = [];
   var params      = {};
   queryString     = queryString.replace(/.*?\?/,"");

   if (queryString.length)
   {
      keyValPairs = queryString.split('&');
      for (pairNum in keyValPairs)
      {
         var key = keyValPairs[pairNum].split('=')[0];
         if (!key.length) continue;
         if (typeof params[key] === 'undefined')
         params[key] = [];
         params[key].push(keyValPairs[pairNum].split('=')[1]);
      }
   }
   return params;
}


var url    = "/pages/new?name=L&return_url=/page/new";
var params = getParams(url);
params['name'];

---

Update

Though still not supported in any version of IE, URLSearchParams provides a native way of retrieving values for other browsers.

虽然在任何版本的IE中仍然不支持URLSearchParams，但是它为其他浏览器提供了一种获取值的本地方法。

#2

Improving on previous answers:

改善之前的答案:

/**
 *
 * @param {string} name
 * @returns {string|null}
 */
function getQueryParam(name) {
  var q = window.location.search.match(new RegExp('[?&]' + name + '=([^&#]*)'));
  return q && q[1];
}

getQueryParam('a'); // returns '1' on page http://domain.com/page.html?a=1&b=2 

#3

The accepted answer includes the hash part if there is a hash right after the params. As @bishoy has in his function, the correct regex would be

接受的答案包括哈希部分，如果在解析之后有哈希部分。正如@bishoy在其函数中所说，正确的regex将是

/name=([^&#]*)/

#4

The following should work:

以下工作:

\?name=(.*?)&

#5

here is the full function (tested and fixed for upper/lower case)

这是完整的函数(测试和固定的大小写)

function getParameterByName (name) 
{
    name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
    var regexS = "[\\?&]" + name.toLowerCase() + "=([^&#]*)";
    var regex = new RegExp(regexS);
    var results = regex.exec(window.location.search.toLowerCase());
    if (results == null)
        return "";
    else
        return decodeURIComponent(results[1].replace(/\+/g, " "));
}

#6

var myname = str.match(/\?name=([^&]+)&/)[1];

The [1] is because you apparently want the value of the group (the part of the regex in brackets).

[1]是因为您显然需要组的值(方括号中regex的部分)。

var str = "/pages/new?name=reaojr&return_url=/page/new";
var matchobj = str.match(/\?name=([^&]+)&/)[1];
document.writeln(matchobj); // prints 'reaojr'