I have a data table and want to extract every fifth row from it to create a new table. Is there a command to achieve this?
我有一个数据表,并希望从中提取每五行以创建一个新表。是否有命令实现这一目标?
Here is an sample of my data:
以下是我的数据示例:
count Idf_Nr block
1 1233 B12
2 1233 B12
3 1446 B12
4 1446 B12
5 365 B12
6 365 B12
7 876 B12
8 876 B12
9 842 B12
10 842 B12
11 1092 B12
12 1092 B12
13 923 B12
14 923 B12
15 1266 B12
16 1266 B12
17 256 B12
18 256 B12
19 588 B12
20 588 B12
21 1074 B12
22 1074 B12
23 474 B12
24 474 B12
25 1421 B12
2 个解决方案
#1
15
For a data frame df, you can get df.new as:
对于数据框df,您可以将df.new作为:
df.new = df[seq(1, nrow(df), 5), ]
This creates an index from row 1 to nrow (number of rows of the table) every 5 rows. You can play with the starting point and the 5 to extract other sequences.
这将从每行5行创建第1行到第n行(表的行数)的索引。您可以使用起点和5来提取其他序列。
#2
4
If you want to extract 5,10...
如果你想提取5,10 ......
newdf <- df[c(rep(FALSE,4),TRUE), ]
If 1,6,11,
newdf <- df[c(TRUE,rep(FALSE,4)), ]
#1
15
For a data frame df, you can get df.new as:
对于数据框df,您可以将df.new作为:
df.new = df[seq(1, nrow(df), 5), ]
This creates an index from row 1 to nrow (number of rows of the table) every 5 rows. You can play with the starting point and the 5 to extract other sequences.
这将从每行5行创建第1行到第n行(表的行数)的索引。您可以使用起点和5来提取其他序列。
#2
4
If you want to extract 5,10...
如果你想提取5,10 ......
newdf <- df[c(rep(FALSE,4),TRUE), ]
If 1,6,11,
newdf <- df[c(TRUE,rep(FALSE,4)), ]