I have this piece of code, I don't understand why it is displaying this error?
我有这段代码,我不明白它为什么显示这个错误?
string messege = "aaa";
char tmp[50];
strcpy_s(tmp, messege.length(), messege.c_str);
char* s = NULL;
s = &(tmp[0]);
Can someone help?
有人可以帮忙吗?
2 个解决方案
#1
0
In this line, you've forgotten the parentheses after the call to c_str:
在这一行中,您在调用c_str后忘记了括号:
strcpy_s(tmp, messege.length(), messege.c_str);
Adding the missing parentheses should fix this.
添加缺少的括号应该解决这个问题。
That said, it's unusual to want to mix C-style and C++-style strings this way. You may want to think about whether what you're doing is appropriate.
也就是说,想要以这种方式混合C风格和C ++风格的字符串是不寻常的。您可能想要考虑您所做的事情是否合适。
#2
0
c_str is a member function of std::string, so you need to call it with ()
c_str是std :: string的成员函数,所以你需要用()调用它
strcpy_s(tmp, messege.length(), messege.c_str());
This will solve your problem.
这将解决您的问题。
#1
0
In this line, you've forgotten the parentheses after the call to c_str:
在这一行中,您在调用c_str后忘记了括号:
strcpy_s(tmp, messege.length(), messege.c_str);
Adding the missing parentheses should fix this.
添加缺少的括号应该解决这个问题。
That said, it's unusual to want to mix C-style and C++-style strings this way. You may want to think about whether what you're doing is appropriate.
也就是说,想要以这种方式混合C风格和C ++风格的字符串是不寻常的。您可能想要考虑您所做的事情是否合适。
#2
0
c_str is a member function of std::string, so you need to call it with ()
c_str是std :: string的成员函数,所以你需要用()调用它
strcpy_s(tmp, messege.length(), messege.c_str());
This will solve your problem.
这将解决您的问题。