【题目链接】:http://codeforces.com/contest/816/problem/B
【题意】
给你很多个区间[l,r];
1<=l<=r<=2e5
一个数字如果被k个以上的区间覆盖到;
则称之为特殊数字;
给你q个询问区间;
问你这q个区间里面
每个区间里面有多少个特殊数字;
【题解】
对于覆盖的区间l,r
add[l]++,sub[r+1]++,
然后顺序枚举
now+=add[i];
now-=sub[i];
如果now>=k则i是一个特殊数字;
写个前缀和O(1)输出答案.
【Number Of WA】
0
【完整代码】
#include <bits/stdc++.h>
using namespace std;
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define LL long long
#define rep1(i,a,b) for (int i = a;i <= b;i++)
#define rep2(i,a,b) for (int i = a;i >= b;i--)
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define ms(x,y) memset(x,y,sizeof x)
#define Open() freopen("F:\\rush.txt","r",stdin)
#define Close() ios::sync_with_stdio(0)
typedef pair<int,int> pii;
typedef pair<LL,LL> pll;
const int dx[9] = {0,1,-1,0,0,-1,-1,1,1};
const int dy[9] = {0,0,0,-1,1,-1,1,-1,1};
const double pi = acos(-1.0);
const int N = 2e5+100;
int add[N],sub[N],n,k,q;
int is[N],sum[N];
int main(){
//Open();
Close();
cin >> n >> k >> q;
rep1(i,1,n){
int x,y;
cin >> x >> y;
add[x]++,sub[y+1]++;
}
int now = 0;
rep1(i,1,(int) 2e5){
now+=add[i];
now-=sub[i];
if (now>=k){
is[i] = 1;
}
}
sum[0] = 0;
rep1(i,1,(int) 2e5){
sum[i] = sum[i-1] + is[i];
}
rep1(i,1,q){
int x,y;
cin >> x >> y;
cout << sum[y]-sum[x-1] << endl;
}
return 0;
}