This question already has an answer here:
这个问题在这里已有答案:
- How to add anchor tag to a URL from text input 7 answers
如何从文本输入7答案添加锚标记到URL
I know the question title looks very repetitive. But some of the solution i did not find here.
我知道问题标题看起来非常重复。但是我在这里找不到一些解决方案。
I need to find urls form text string:
我需要找到url表单文本字符串:
$pattern = '`.*?((http|https)://[\w#$&+,\/:;=?@.-]+)[^\w#$&+,\/:;=?@.-]*?`i';
if (preg_match_all($pattern,$url_string,$matches)) {
print_r($matches[1]);
}
using this pattern i was able to find urls with http://
and https://
which is okey. But i have user input where people add url like www.domain.com
even domain.com
使用这种模式,我能够找到http://和https://的网址,这是okey。但我有用户输入,人们添加网址,如www.domain.com甚至domain.com
So, i need to validate the string first where i can replace www.domain.com
domain.com
with common protocol http://
before them. Or i need to comeup with more good pattern?
因此,我需要首先验证字符串,然后我可以使用通用协议http://替换www.domain.com domain.com。或者我需要提出更好的模式?
I am not good with regex and don't know what to do.
我对正则表达式不好,不知道该怎么做。
My idea is first finding the urls with http://
and https://
the put them in an array then replace these url with space(" ") in the text string then use other patterns for it. But i am not sure what pattern to use.
我的想法是首先找到带有http://和https://的网址,然后将它们放入数组中,然后在文本字符串中用空格(“”)替换这些网址,然后使用其他模式。但我不确定使用什么模式。
I am using this $url_string = preg_replace($pattern, ' ', $url_string );
but that removes if any www.domain.com
or domain.com
url between two valid url with http://
or https://
我正在使用$ url_string = preg_replace($ pattern,'',$ url_string);但如果任何www.domain.com或domain.com网址在http://或https://两个有效网址之间移除,则会删除
If you can help that will be great.
如果你能提供帮助就会很棒。
To make things more clear:
为了使事情更清楚:
i need a pattern or some other method where i can find all urls in a text sting. the example of url are:
我需要一个模式或其他方法,我可以在文本刺痛中找到所有网址。 url的例子是:
- domain.com
- www.domain.com
- http://www.domain.com
- http://domain.com
- https://www.domain.com
- https://domain.com
thanks! 5.
2 个解决方案
#1
3
$pattern = '#(www\.|https?://)?[a-z0-9]+\.[a-z0-9]{2,4}\S*#i';
preg_match_all($pattern, $str, $matches, PREG_PATTERN_ORDER);
#2
0
I'm not sure if I've understood what you need correctly, but can you use something like this:
我不确定我是否理解你需要的东西,但你可以使用这样的东西:
preg_match('#^.+?://#', $url);
to find if there is a protocol specified on the string, and if not just append http://
找出是否在字符串上指定了协议,如果不是只是附加http://
#1
3
$pattern = '#(www\.|https?://)?[a-z0-9]+\.[a-z0-9]{2,4}\S*#i';
preg_match_all($pattern, $str, $matches, PREG_PATTERN_ORDER);
#2
0
I'm not sure if I've understood what you need correctly, but can you use something like this:
我不确定我是否理解你需要的东西,但你可以使用这样的东西:
preg_match('#^.+?://#', $url);
to find if there is a protocol specified on the string, and if not just append http://
找出是否在字符串上指定了协议,如果不是只是附加http://