Clojure + Linux + Ext4 +将字符串编码为文件名

Background:

I am using Clojure, on Java 7.0 on Ubuntu Linux 12.10, with an Ext4 file system.

我正在使用Clojure,在Ubuntu Linux 12.10上的Java 7.0上,使用Ext4文件系统。

Problem:

I have an arbitrary Clojure string. I would like to encode it into a valid filename.

我有一个任意的Clojure字符串。我想将其编码为有效的文件名。

Question:

What is the optimal way / what is a good builtin for doing this?

什么是最佳方式/什么是良好的内置这样做?

Note:

The encoded file name does not have to be human readable. I just need to be able to recover the original string from the filename.

编码的文件名不必是人类可读的。我只需要能够从文件名中恢复原始字符串。

EDIT:

Although if strings that are valid names gets mapped to something that is human readbale (and close to it's original value, that would be nice too.)

虽然如果有效名称的字符串被映射到人类readbale的东西(并且接近它的原始值,那也很好。)

Thanks!

EDIT:

encode: takes arbitrary string as input; creates valid filename as output

encode:将任意字符串作为输入;创建有效文件名作为输出

decode: takes file name from encode, recovers original string

decode:从编码中获取文件名,恢复原始字符串

1 个解决方案

If it doesn't need to be human readable, just base64 encode it. That will remove any file name invalid characters from the string.

如果它不需要是人类可读的,只需对base64进行编码即可。这将从字符串中删除任何文件名无效字符。

If they still don't have a decoder in native clojure, use a Java base64 decode function.

如果他们仍然没有本机clojure中的解码器,请使用Java base64解码功能。

If it doesn't need to be human readable, just base64 encode it. That will remove any file name invalid characters from the string.

如果它不需要是人类可读的,只需对base64进行编码即可。这将从字符串中删除任何文件名无效字符。

If they still don't have a decoder in native clojure, use a Java base64 decode function.

如果他们仍然没有本机clojure中的解码器,请使用Java base64解码功能。