I am trying to convert UTF-8 string to C/POSIX locale string
The UTF-8 string is "abc123£" (in bash "abc123\302\243"`)
我试图将UTF-8字符串转换为C / POSIX语言环境字符串UTF-8字符串是“abc123£”(在bash“abc123 \ 302 \ 243”中)
- iconv_open("", "UTF-8"); // "" means default program locale i.e. C
- iconv_open("UCS-2LE", "UTF-8");
iconv_open(“”,“UTF-8”); //“”表示默认程序区域设置,即C.
iconv() is returning EILSEQ to me in case 1, but success in case 2.
iconv()在案例1中将EILSEQ返回给我,但在案例2中成功。
What is the reason for this?
Also, how can I successfully convert any UTF-8 string to 'C' locale string.
这是什么原因?另外,如何将任何UTF-8字符串成功转换为“C”语言环境字符串。
1 个解决方案
#1
1
Because your C locale uses a character set (probably US-ASCII) that doesn't have a character for £, and the string can't be converted without loss.
因为您的C语言环境使用的字符集(可能是US-ASCII)没有£的字符,并且无法在不丢失的情况下转换字符串。
#1
1
Because your C locale uses a character set (probably US-ASCII) that doesn't have a character for £, and the string can't be converted without loss.
因为您的C语言环境使用的字符集(可能是US-ASCII)没有£的字符,并且无法在不丢失的情况下转换字符串。