I'm creating a cron job in a script like this:
我正在这样的脚本中创建一个cron作业:
DIR="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"
crontab -l > crontask
grep "* * * * * $DIR/somescript" crontask || echo "* * * * * $DIR/somescript" >> crontask
I'd like to build a script that can delete this job, how should I do that?
我想建立一个可以删除这份工作的脚本,我应该怎么做?
1 个解决方案
#1
-1
A quick google search and you got it :
快速谷歌搜索,你得到它:
crontab -l | grep -v "* * * * * $DIR/somescript" | crontab -
And to add a cron task :
并添加一个cron任务:
{ crontab -l ; echo "* * * * * $DIR/somescript"; } | crontab -
#1
-1
A quick google search and you got it :
快速谷歌搜索,你得到它:
crontab -l | grep -v "* * * * * $DIR/somescript" | crontab -
And to add a cron task :
并添加一个cron任务:
{ crontab -l ; echo "* * * * * $DIR/somescript"; } | crontab -