I have three tables,
我有三张桌子,
products has 3 columns, let them be product_id,retailer_id,id
产品有3列,让它们是product_id,retailer_id,id
product_urls has 2 columns, url_id,id
product_urls有2列,url_id,id
urls has 2 columns, url_id, absolute_url
urls有2列,url_id,absolute_url
All the associations has been done in models.
所有协会都是在模型中完成的。
Products & product_urls are joined on id = id (Products "has many" relationship with product_urls)
产品和product_urls在id = id上加入(产品“与product_urls有很多关系”)
product_urls & urls are joined on Url_id = id (product_urls "belongs to" relationship with urls)
product_urls和url在Url_id = id上加入(product_urls“属于”与url的关系)
products & urls have "has many relationship"
产品和网址“有很多关系”
I am trying to write a query, which selects A,B,C column from Table1 and X from Table3.
我正在尝试编写一个查询,它从Table1中选择A,B,C列,从Table3中选择X.
My query is:
我的查询是:
- Product.joins(:urls).select(:product_id,:retailer_id,:absolute_url).where(:id=>100, :urls => {:url_id=>100})
Product.joins(:urls).select(:product_id,:retailer_id,:absolute_url).where(:id => 100,:urls => {:url_id => 100})
I am able to execute the query without any error, but I am not able to get data for X. when I check for sql query it is
我能够执行查询没有任何错误,但我无法获取X的数据。当我检查sql查询它是
- select products.product_id, products.retailer_id, products.absolute_url ........ is executed.
选择products.product_id,products.retailer_id,products.absolute_url ........执行。
Please help me how to fetch value from urls??
请帮我如何从网址获取价值?
1 个解决方案
#1
1
Try the below code
请尝试以下代码
Product.joins(:urls).select("products.product_id,products.retailer_id,urls.absolute_url").where(:id=>100, :urls => {:url_id=>100})
#1
1
Try the below code
请尝试以下代码
Product.joins(:urls).select("products.product_id,products.retailer_id,urls.absolute_url").where(:id=>100, :urls => {:url_id=>100})