c#从数组中删除字符串

时间:2022-06-19 07:41:09

How can i remove any strings from an array and have only integers instead

我如何从数组中删除任何字符串,而只有整数

string[] result = col["uncheckedFoods"].Split(',');

I have

[0] = on;      // remove this string
[1] = 22;
[2] = 23;
[3] = off;      // remove this string
[4] = 24;

I want

[0] = 22;
[1] = 23;
[2] = 24;

I tried

var commaSepratedID = string.Join(",", result);

var data = Regex.Replace(commaSepratedID, "[^,0-9]+", string.Empty);

But there is a comma before first element, is there any better way to remove strings ?

但是在第一个元素之前有一个逗号,有没有更好的方法来删除字符串?

3 个解决方案

#1


10  

This selects all strings which can be parsed as int

这将选择可以解析为int的所有字符串

string[] result = new string[5];
result[0] = "on";      // remove this string
result[1] = "22";
result[2] = "23";
result[3] = "off";      // remove this string
result[4] = "24";
int temp;
result = result.Where(x => int.TryParse(x, out temp)).ToArray();

#2


0  

To also support double I would do something like this:

为了支持双倍,我会做这样的事情:

public static bool IsNumeric(string input, NumberStyles numberStyle)
{
   double temp;
   return Double.TryParse(input, numberStyle, CultureInfo.CurrentCulture, out temp);
}

and then

string[] result = new string[] {"abc", "10", "4.1" };
var res = result.Where(b => IsNumeric(b, NumberStyles.Number));
// res contains "10" and "4.1"

#3


0  

Try this

  dynamic[] result = { "23", "RT", "43", "67", "gf", "43" };

                for(int i=1;i<=result.Count();i++)
                {
                    var getvalue = result[i];
                    int num;
                    if (int.TryParse(getvalue, out num))
                    {
                        Console.Write(num);
                        Console.ReadLine();
                        // It's a number!
                    }
                }

#1


10  

This selects all strings which can be parsed as int

这将选择可以解析为int的所有字符串

string[] result = new string[5];
result[0] = "on";      // remove this string
result[1] = "22";
result[2] = "23";
result[3] = "off";      // remove this string
result[4] = "24";
int temp;
result = result.Where(x => int.TryParse(x, out temp)).ToArray();

#2


0  

To also support double I would do something like this:

为了支持双倍,我会做这样的事情:

public static bool IsNumeric(string input, NumberStyles numberStyle)
{
   double temp;
   return Double.TryParse(input, numberStyle, CultureInfo.CurrentCulture, out temp);
}

and then

string[] result = new string[] {"abc", "10", "4.1" };
var res = result.Where(b => IsNumeric(b, NumberStyles.Number));
// res contains "10" and "4.1"

#3


0  

Try this

  dynamic[] result = { "23", "RT", "43", "67", "gf", "43" };

                for(int i=1;i<=result.Count();i++)
                {
                    var getvalue = result[i];
                    int num;
                    if (int.TryParse(getvalue, out num))
                    {
                        Console.Write(num);
                        Console.ReadLine();
                        // It's a number!
                    }
                }