OK, so I've got this line of code in a search stored procedure:
我在搜索存储过程中有这一行代码
SET @where = 'job_code = ''' + REPLACE(@job_code, '''', '''''') + ''''
and there are basically two operations I'd like to streamline -the first being surrounding the concatenated value in single quotes. Obviously, in the above statement, I'm escaping a '
by using two ''
and then ending the string with a '
so I can concatenate the actual value. There's got to be a better way!
基本上有两个操作我想要流线化-第一个是围绕在单引号的连接值。显然,在上面的语句中,我用两个来转义一个',然后用一个'来结束字符串,这样我就可以把实际的值串联起来。一定有更好的办法!
The second of the operations would be the REPLACE(@job_code, '''', '''''')
where I'm escaping any single quotes that might exist in the field.
第二个操作是REPLACE(@job_code, " ", " "),在这里我将转义字段中可能存在的任何单引号。
Isn't there a much more elegant way of writing this line of code as a whole?
难道没有一种更优雅的方式来作为一个整体来编写这行代码吗?
I thought it was the ESCAPE
keyword but that's tied tightly to the LIKE
statement, so no go there.
我以为它是ESCAPE关键字,但它与LIKE语句紧密相连,所以不去那里。
4 个解决方案
#1
26
Not sure how you execute your sql query, if you use sp_executesql, could be something like this
不确定如何执行sql查询,如果使用sp_executesql,可能是这样的
EXECUTE sp_executesql
N'SELECT * FROM YouTable WHERE job_code = @job_code',
N'@job_code varchar(100)',
@job_code = @job_code;
#2
5
The parameterized query answer is probably the real "right answer", but to answer your original question, what you want is QUOTENAME(). More specifically, the single-quote version:
参数化查询答案可能是真正的“正确答案”,但是要回答最初的问题,您需要的是QUOTENAME()。更具体地说,单引号版本:
SET @where = 'job_code = ' + QUOTENAME(@job_code, '''')
Do note the length limit on this (input is a sysname
, meaning 128 characters), though, as it is intended to quote the names of database objects and not as a general-purpose mechanism.
请注意这一点的长度限制(输入是一个sysname,意思是128个字符),因为它的目的是引用数据库对象的名称,而不是作为一种通用的机制。
#3
2
You could declare constants:
你可以声明常量:
declare @SQ as char(1) = ''''
SET @where = 'job_code = ' + @SQ + REPLACE(@job_code, @SQ, @SQ + @SQ) + @SQ
#4
2
You could define a function that handles your typical scenarios, something like:
您可以定义一个处理典型场景的函数,例如:
create function WrapAndReplaceQuotes (@input as varchar(max))
returns varchar(max)
as
begin
return '''' + replace(@input, '''', '''''') + ''''
end
SET @where = 'job_code = ' + WrapAndReplaceQuotes(@job_code)
#1
26
Not sure how you execute your sql query, if you use sp_executesql, could be something like this
不确定如何执行sql查询,如果使用sp_executesql,可能是这样的
EXECUTE sp_executesql
N'SELECT * FROM YouTable WHERE job_code = @job_code',
N'@job_code varchar(100)',
@job_code = @job_code;
#2
5
The parameterized query answer is probably the real "right answer", but to answer your original question, what you want is QUOTENAME(). More specifically, the single-quote version:
参数化查询答案可能是真正的“正确答案”,但是要回答最初的问题,您需要的是QUOTENAME()。更具体地说,单引号版本:
SET @where = 'job_code = ' + QUOTENAME(@job_code, '''')
Do note the length limit on this (input is a sysname
, meaning 128 characters), though, as it is intended to quote the names of database objects and not as a general-purpose mechanism.
请注意这一点的长度限制(输入是一个sysname,意思是128个字符),因为它的目的是引用数据库对象的名称,而不是作为一种通用的机制。
#3
2
You could declare constants:
你可以声明常量:
declare @SQ as char(1) = ''''
SET @where = 'job_code = ' + @SQ + REPLACE(@job_code, @SQ, @SQ + @SQ) + @SQ
#4
2
You could define a function that handles your typical scenarios, something like:
您可以定义一个处理典型场景的函数,例如:
create function WrapAndReplaceQuotes (@input as varchar(max))
returns varchar(max)
as
begin
return '''' + replace(@input, '''', '''''') + ''''
end
SET @where = 'job_code = ' + WrapAndReplaceQuotes(@job_code)