如何将django的设置对象变成dict？

What I have:

我拥有的:

from django.conf import settings

def settings_to_dict(settings)
    cfg = {
        'BOTO3_ACCESS_KEY': settings.BOTO3_ACCESS_KEY,
        'BOTO3_SECRET_KEY': settings.BOTO3_SECRET_KEY,
        # repeat ad nauseum
    }
    return cfg

instance = SomeClassInstantiatedWithADict(**settings_to_dict(settings))

What I'd like (using Django 1.11):

我想要什么(使用Django 1.11):

from django.conf import settings

instance = SomeClassInstantiatedWithADict(**settings.to_dict())

I've tried:

from django.conf import settings

instance = SomeClassInstantiatedWithADict(**settings.__dict__)

which is close, but __dict__ only gets a small subset of the settings, which I assume are hard coded ones as opposed to added attributes. Thanks for any help!

虽然很接近,但是__dict__只获得了一小部分设置,我认为它们是硬编码的,而不是添加属性。谢谢你的帮助!

4 个解决方案

#1

Use the following code:

使用以下代码:

from django.conf import settings
instance = settings.__dict__['_wrapped'].__dict__

Then you will have the whole settings dict in instance as dictionary.

然后你将整个设置dict作为字典实例。

#2

This turns the entire settings object into a dictionary:

这会将整个设置对象转换为字典:

In [12]: settings_dict = {}

In [13]: for st in dir(settings):
    ...:     if st.startswith('_'):
    ...:         continue
    ...:     settings_dict[st] = getattr(settings, st)
    ...:
    ...:

In [14]: settings_dict

This is very exhaustive and it contains all possible attributes of settings.

这非常详尽,它包含所有可能的设置属性。

dir() is a Python builtin. Read about it here

dir()是一个内置的Python。在这里阅读它

#3

Check settings.__dict__['_wrapped'].__dict__ in your shell. It seems there is everything inside. Not sure however if it's the right way to access this.

在你的shell中检查设置.__ dict __ ['_ wrapped'] .__ dict__。似乎里面有一切。但是不确定这是否是访问它的正确方法。

#4

>>> from django.conf import settings
>>> settings_dict = vars(settings._wrapped)
>>> print(settings_dict)
{'ABSOLUTE_URL_OVERRIDES': {}, 'ADMINS': [], 'ALLOWED_HOSTS': ['127.0.0.1', 'localhost', 'www.tetricoins.com', 'api.tetricoins.com'], 'APPEND_SLASH': True, ...

#1