array = [[1, 2, 3], [8, 9, 4], [7, 6, 5]]
I keep getting it in a single line, how can I print it out in the terminal so each array is on its own individual line like so:
我一直把它放在一行，如何在终端中打印出来，这样每个阵列都在各自的行上，如下所示：
[[1, 2, 3],
[8, 9, 4],
[7, 6, 5]]
4 个解决方案
#1
2
Try printing the mapped result of #inspect on array, like so:
尝试在数组上打印#inspect的映射结果，如下所示：
puts array.map(&:inspect)
# [1, 2, 3]
# [8, 9, 4]
# [7, 6, 5]
Hope this helps!
希望这可以帮助！
#2
2
The following should work:
以下应该有效：
array.each do |sub|
puts sub.join(", ")
end
However, this will not include the [] characters, but will look like this:
但是，这不包括[]字符，但是看起来像这样：
1, 2, 3
8, 9, 4
7, 6, 5
#3
2
array = [[1, 2, 3], [8, 9, 4], [7, 6, 5]]
puts array.to_s.gsub('],',"],\n")
#[[1, 2, 3],
# [8, 9, 4],
# [7, 6, 5]]
#4
2
Just for fun - you can redefine inspect method like:
只是为了好玩 - 您可以重新定义检查方法，如：
def array.inspect
map(&:to_s).join("\n")
end
p array
# [1, 2, 3]
# [8, 9, 4]
# [7, 6, 5]
#1
2
Try printing the mapped result of #inspect on array, like so:
尝试在数组上打印#inspect的映射结果，如下所示：
puts array.map(&:inspect)
# [1, 2, 3]
# [8, 9, 4]
# [7, 6, 5]
Hope this helps!
希望这可以帮助！
#2
2
The following should work:
以下应该有效：
array.each do |sub|
puts sub.join(", ")
end
However, this will not include the [] characters, but will look like this:
但是，这不包括[]字符，但是看起来像这样：
1, 2, 3
8, 9, 4
7, 6, 5
#3
2
array = [[1, 2, 3], [8, 9, 4], [7, 6, 5]]
puts array.to_s.gsub('],',"],\n")
#[[1, 2, 3],
# [8, 9, 4],
# [7, 6, 5]]
#4
2
Just for fun - you can redefine inspect method like:
只是为了好玩 - 您可以重新定义检查方法，如：
def array.inspect
map(&:to_s).join("\n")
end
p array
# [1, 2, 3]
# [8, 9, 4]
# [7, 6, 5]