重声明—如果数组有多个值，则重复此函数

function test($str) {
  $c = count($str);
  if ($c>1) {
    foreach ($str as $key => $value) $result .= test($value);
  } else {
    $result = "<li>$str</li>\n";
  }
  echo $result ? "<ol>$result</ol>" : null;
}

The $str value could be either, something like this;

$str值可以是这样的;

$str1 = "apple";

or something like that;

之类的;

$str2 = array("apple","orange","pear");

If count($str) is more than one, which is $str is is_array, it repeats the $result.
But it doesn't work as I want..
I get an error "Cannot redeclare test() (previously declared in..."

如果count($str)大于1，即$str是is_array，则重复$result。但这并不是我想要的。我得到一个错误“无法重新声明test()”(之前在…中声明的)

The ideal output would be - $str1;

理想的输出是- $str1;

<ol>
  <li>apple</li>
</ol>

The ideal output would be - $str2;

理想的输出是- $str2;

<ol>
  <li>apple</li>
  <li>orange</li>
  <li>pear</li>
</ol>

3 个解决方案

#1

Check, if $str is an array, e.g.:

检查，如果$str是一个数组，例如:

function test($str, $first=true) {
  if (!is_array($str)) {
    $result = "<li>$str</li>\n";
  } else {
    foreach ($str as $key => $value) $result .= test($value, false);
  }
  return ($first ? "<ol>$result</ol>" : $result);
}

Also see this example.

也看到这个例子。

=== UPDATE ===

= = = = = =更新

If you want to let it print directly, replace with:

如果你想让它直接打印，可以用:

function test($str, $first=true) {
  if (!is_array($str)) $result = "<li>$str</li>";
  else foreach ($str as $key => $value) $result .= test($value, false);
  if ($first) echo "<ol>$result</ol>";
  else return $result;
}

Also see this example.

也看到这个例子。

#2

function test($str) {

  // Ensure, $str is a good argument of implode()
  if ( ! is_array( $str )) {
    $str = array( $str );
  }

  $result = '<li>' . implode( '</li><li>', $str ) . '</li>';

  return '<ol>' . $result . '</ol>';

}

Remark: Your method could return this:

注:您的方法可以返回:

<ol>
  <li>1</li>
  <li>
  <ol>
    <li>1</li>
    <li>2</li>
    <li>3</li>
  </ol>
  </li>
  <li>3</li>
</ol>

Does this is really what you want to achieve? Does it really need to create nested OL structures?

这真的是你想要实现的吗?它真的需要创建嵌套OL结构吗?

#3

function testInternal($str){
    if(is_array($str))
        return implode('',array_map('testInternal', $str));
    else
        return '<li>'.$str.'</li>';
}
function test($str){
    echo '<ol>'.testInternal($str).'</ol>';
}