如何获得当前行号?

Here is an example of what I want to do:

下面是我想做的一个例子:

 MessageBox.Show("Error line number "+CurrentLineNumber);

Current line number will be the line number in the source code of this piece of code.

当前行号将是这段代码的源代码中的行号。

How can I do that?

我怎么做呢?

7 个解决方案

#1

115

In .NET 4.5 / C# 5, you can get the compiler to do this work for you, by writing a utility method that uses the new caller attributes:

在。net 4.5 / c# 5中，通过编写使用新的调用者属性的实用方法，您可以让编译器为您完成这项工作:

static void SomeMethodSomewhere()
{
    ShowMessage("Boo");
}
...
static void ShowMessage(string message,
    [CallerLineNumber] int lineNumber = 0,
    [CallerMemberName] string caller = null)
{
     MessageBox.Show(message + " at line " + lineNumber + " (" + caller + ")");
}

This will display, for example:

这将显示，例如:

Boo at line 39 (SomeMethodSomewhere)

第39行嘘声(某些地方)

There's also [CallerFilePath] which tells you the path of the original code file.

还有[CallerFilePath]，它告诉您原始代码文件的路径。

#2

Use the StackFrame.GetFileLineNumber method, for example:

使用StackFrame。GetFileLineNumber方法,例如:

private static void ReportError(string message)
{
     StackFrame callStack = new StackFrame(1, true);
     MessageBox.Show("Error: " + message + ", File: " + callStack.GetFileName() 
          + ", Line: " + callStack.GetFileLineNumber());
}

See Scott Hanselman's Blog entry for more information.

更多信息请参见Scott Hanselman的博客文章。

[Edit: Added the following]

(编辑:添加以下)

For those using .Net 4.5 or later, consider the CallerFilePath, CallerMethodName and CallerLineNumber attributes in the System.Runtime.CompilerServices namespace. For example:

对于那些使用。net 4.5或更高版本的用户，请考虑System.Runtime中的CallerFilePath、CallerMethodName和CallerLineNumber属性。CompilerServices名称空间。例如:

public void TraceMessage(string message,
        [CallerMemberName] string callingMethod = string.Empty,
        [CallerFilePath] string callingFilePath = string.Empty,
        [CallerLineNumber] int callingFileLineNumber = 0)
{
    // Write out message
}

The arguments must be string for CallerMemberName and CallerFilePath and an int for CallerLineNumber and must have a default value. Specifying these attributes on method parameters instructs the compiler to insert the appropriate value in the calling code at compile time, meaning it works through obfuscation. See Caller Information for more information.

参数必须是CallerMemberName和CallerFilePath的字符串，以及CallerLineNumber的int，并且必须有一个默认值。在方法参数上指定这些属性可以指示编译器在编译时在调用代码中插入适当的值，这意味着它可以通过模糊处理工作。有关更多信息，请参见呼叫者信息。

#3

I prefer one liners so:

我更喜欢一个笑话:

int lineNumber = (new System.Diagnostics.StackFrame(0, true)).GetFileLineNumber();

#4

For those who need a .NET 4.0+ method solution:

对于那些需要。net 4.0+方法解决方案的人:

using System;
using System.IO;
using System.Diagnostics;

public static void Log(string message) {
   StackFrame stackFrame = new System.Diagnostics.StackTrace(1).GetFrame(1);
   string fileName = stackFrame.GetFileName();
   string methodName = stackFrame.GetMethod().ToString();
   int lineNumber = stackFrame.GetFileLineNumber();

   Console.WriteLine("{0}({1}:{2})\n{3}", methodName, Path.GetFileName(fileName), lineNumber, message);
}

How to call:

如何调用:

void Test() {
   Log("Look here!");
}

Output:

输出:

Void Test()(FILENAME.cs:104)

空白测试()(FILENAME.cs:104)

Look here!

看过来！

Change the Console.WriteLine format how you like!

更改控制台。写格式你喜欢!

#5

If its in a try catch block use this.

如果它在尝试捕捉块使用这个。

try
{
    //Do something
}
catch (Exception ex)
{
    System.Diagnostics.StackTrace trace = new System.Diagnostics.StackTrace(ex, true);
    Console.WriteLine("Line: " + trace.GetFrame(0).GetFileLineNumber());
}

#6

In .NET 4.5 you can get the line number by creating the function:

在。net 4.5中，你可以通过创建函数来获取行号:

static int LineNumber([System.Runtime.CompilerServices.CallerLineNumber] int lineNumber = 0)
{
    return lineNumber; 
}

Then each time you call LineNumber() you will have the current line. This has the advantage over any solution using the StackTrace that it should work in both debug and release.

然后，每次调用LineNumber()时，您将拥有当前行。与使用StackTrace的任何解决方案相比，这都有一个优点，即它应该在调试和发布中工作。

So taking the original request of what is required, it would become:

因此，按照最初的要求，它将变成:

MessageBox.Show("Error enter code here line number " + LineNumber());

This is building on the excellent answer by Marc Gravell.

这是基于Marc Gravell出色的回答。

#7

-7

This works for me:

这工作对我来说:

try
{
 //your code;
}
catch(Exception ex)
{
  MessageBox.Show(ex.StackTrace + " ---This is your line number, bro' :)", ex.Message);
}

#1

115