如何只处理已更改的文件？

At the moment I'm doing this:

目前我正在这样做:

<delete dir="${RSA.dir}/file1" />
<copy todir="${RSA.dir}/file1" >
    <fileset dir="${CLEARCASE.dir}/file1" />            
</copy>

and repeating the same thing for other files - but it takes a long time.

并为其他文件重复相同的事情 - 但这需要很长时间。

I only want to delete and copy files that have been updated, with their modified date in clearcase later than that in RSA.

我只想删除和复制已更新的文件,其修改日期晚于RSA中的明确日期。

How can I do that?

我怎样才能做到这一点?

2 个解决方案

#1

Look into the sync task.

查看同步任务。

If you want to do it based on file contents, and ignore the timestamp, I think this macro will do that:

如果你想根据文件内容来做,并忽略时间戳,我认为这个宏会这样做:

<macrodef name="mirror" description="Copy files only if different; remove files that do not exist in dir. This works similiar to robocopy /MIR." >
    <attribute name="dir"/>
    <attribute name="todir"/>
    <sequential>
        <copy overwrite="true" todir="@{todir}">
            <fileset dir="@{dir}">
                <different targetdir="${todir}"/>
            </fileset>
        </copy>
        <delete includeemptydirs="true">
            <fileset dir="@todir}">
                <present targetdir="${dir}" present="srconly"/>
            </fileset>                
        </delete>
    </sequential>
</macrodef>

#2

You need to use a selector on a FileSet. Something like this:

您需要在FileSet上使用选择器。像这样的东西:

<fileset dir="${your.working.dir}/src/main" includes="**/*.java">
    <different targetdir="${clean.clearcase.checkout}/src/main"
        ignoreFileTimes="false"
        ignoreContents="true" />
</fileset>

That compares your working dir to a clean checkout you have elsewhere, and returns the files whose last modified times have changed. You can use the fileset as the argument for a <delete> or a <copy>.

这会将您的工作目录与您在其他地方的清理结帐进行比较,并返回上次修改时间已更改的文件。您可以使用fileset作为或的参数。

#1