插值公式为:
差商递归公式为:
# -*- coding: utf-8 -*-
#Program 0.4 Newton Interpolation import numpy as np
import matplotlib.pyplot as plt #递归求差商
def get_diff_quo(xi, fi):
if len(xi) > 2 and len(fi) > 2:
return (get_diff_quo(xi[:len(xi)-1], fi[:len(fi)-1]) - get_diff_quo(xi[1:len(xi)], fi[1:len(fi)])) / float(xi[0] - xi[-1])
return (fi[0]-fi[1]) / float(xi[0]-xi[1]) #求w,使用闭包函数
def get_w(i, xi):
def wi(x):
result = 1.0
for j in range(i):
result *= (x - xi[j])
return result
return wi #做插值
def get_Newton(xi, fi):
def Newton(x):
result = fi[0]
for i in range(2, len(xi)):
result += (get_diff_quo(xi[:i], fi[:i]) * get_w(i-1, xi)(x))
return result
return Newton #已知结点
xn = [i for i in range(-50, 50, 10)]
fn = [i**2 for i in xn] #插值函数
Nx = get_Newton(xn, fn) #测试用例
tmp_x = [i for i in range(-50, 51)]
tmp_y = [Nx(i) for i in tmp_x] #作图
plt.plot(xn, fn, 'r*')
plt.plot(tmp_x, tmp_y, 'b-')
plt.title('Newton Interpolation')
plt.xlabel('x')
plt.ylabel('y')
plt.show()