s_sub='{"_id":{"$oid":"59b73d80930c17474f9f050d"},"address":"'
s_sub_sub='"}'
r=${s//$s_sub/}
r=${r//$s_sub_sub/}
echo $r expr length '{"_id":{"$oid":"59b73d80930c17474f9f050d"},"address":"' r=${s:55:100}
r=${r//$s_sub_sub/}
echo $r

  

shell变量里的字符替换 - CSDN博客 http://blog.csdn.net/augusdi/article/details/41010041

linux shell 字符串操作详解 (长度,读取,替换,截取,连接,对比,删除,位置 ) - gaomatlab - 博客园 https://www.cnblogs.com/gaochsh/p/6901809.html

大文件处理

awk分割字符串

awk '{split(substr($1,55,100),arr,"\"") ;print arr[1]}' kwaddress_address_20180227.json

awk '{split(substr($1,55,100),arr,"\""); split(arr[1],arr_b,"/");print arr_b[1]}' kwaddress_address_20180227.json

[root@hadoop3 kwaddress]# cat  extract.2g.sh
s_sub_sub='"}'
r=''
s=`awk '{split(substr($1,55,100),arr,"\""); split(arr[1],arr_b,"/");print arr_b[1]}' kwaddress_address_20180227.json`
#for LINE in `cat /home/data/kwaddress/kwaddress_address_20180227.json`
#for LINE in `awk '{print substr($1,55,100)}' kwaddress_address_20180227.json`
for LINE in $s
do
echo $LINE
#r=${LINE:55:100}
# r=${r//$s_sub_sub/}
# echo $r
done echo
exit 0 [root@hadoop3 kwaddress]#

  

awk '{split(substr($1,55,100),arr,"\""); split(arr[1],arr_b,"/");print arr_b[1]}' kwaddress_address_20180227.json >> url.pool.txt

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