在C中实例化一个结构列表。

I'm sure this must have been asked before but I can't seem to find an answer anywhere. I have a struct defined in a header file as so:

我肯定这个问题以前一定有人问过，但我似乎在任何地方都找不到答案。我在头文件中定义了一个结构体，如下所示:

struct lock {
    char *name;
    // add what you need here
    void *holder;
    // (don't forget to mark things volatile as needed)
};

I want to make a list of lock objects. That way I can say something like:

我想做一个锁对象列表。这样我就可以说:

lock_list[0] = create_lock();
lock_list[1] = create_lock();

I tried different ways but they all give me errors. I thought I could simply say:

我尝试了不同的方法，但它们都给了我错误。我想我可以简单地说:

lock[2] lock_list;

but it didn't work. Any help would be much appreciated.

但它不工作。非常感谢您的帮助。

2 个解决方案

#1

If create_lock() returns a pointer to a lock, the following should work:

如果create_lock()返回一个指向锁的指针，则应执行以下操作:

lock *lock_list[2];

Also, since you didn't post it, you need to typedef your struct if you want to be able to omit the struct part when using it:

另外，由于您没有发布它，所以如果您想在使用结构部分时省略结构部分，则需要对其进行typedef:

typedef struct lock lock;

#2

If it's not fixed size, you can produce a linked list:

如果不是固定尺寸，你可以制作一个链表:

typedef struct lock_t lock;
typedef struct lockList_t lockList;

struct lock_t {
    char *name;
    void *holder;
}

struct lockList_t {
    lock lock_entry;
    lockList *lock_next;
}

You can then use an instance of lockList to store a dynamically sized list of locks.

然后，您可以使用一个lockList实例来存储一个动态大小的锁列表。

#1