如何在java中创建链表？ [重复]

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Initialization of an ArrayList in one line 30 answers

在一行30中初始化ArrayList的答案

I would like to write a linked list like this:

我想写一个像这样的链表:

"a" -> "b" -> "c" -> "d"

This is what I've tried so far but it's obviously wrong. I was wondering how to express this correctly in java?

这是我到目前为止所尝试过的,但显然是错误的。我想知道如何在java中正确表达这一点?

LinkedList<String> s = new LinkedList<>();
s = {"a"->"b"->"c"->"d"};

Thanks!

3 个解决方案

#1

That's how the pointers in the list look internally, to actually add it to the list you need to do this:

这就是列表中指针在内部的外观,实际上将它添加到您需要执行此操作的列表中:

List<String> s = new LinkedList<>(); 

s.add("a"); 
s.add("b");
s.add("c");
s.add("d");

#2

Take a look at this answer.

看看这个答案。

LinkedList<String> list = new LinkedList<>();
list.add("a");
list.add("b");
list.add("c");
list.add("d");

If you really want it on one line:

如果你真的想要它在一条线上:

LinkedList<String> list = new LinkedList<>(Arrays.asList("a","b","c","d"));

Though that does have a performance overhead.

虽然这确实有性能开销。

#3

You could do this:

你可以这样做:

LinkedList<String> linkedList = new LinkedList<String>();
    linkedList.add("a");
    linkedList.add("b");
    linkedList.add("c");
    linkedList.add("d");

#1