关闭所有弹出窗口[复制]

This question already has an answer here:

这个问题已经有了答案:

Get list of opened popup windows 2 answers
获取打开的弹出窗口2答案列表

I know there are many questions of this ilk with many answers.

我知道这类问题有很多答案。

I know that I can use

我知道我可以用

var popup = window.open('');

and can later use

并且可以以后使用

popup.close();

to close that window.

关闭窗口。

However, is there a way to close all children without having to store the window.open result?

但是，有没有一种方法可以在不需要存储窗口的情况下关闭所有的孩子。开放的结果吗?

That is, could I do

也就是说，我能做吗

window.open('1');
window.open('2');
window.open('3');

and then somehow do a global "Close" call that will close these three windows?

然后做一个全局“关闭”调用来关闭这三个窗口?

If not, could I accomplish it by using the following code to do the open?

如果没有，我是否可以使用下面的代码来打开它?

window.open('1','window1');
window.open('2','window2');
window.open('3','window3');

2 个解决方案

#1

You can make a new function that basically wraps the existing functionality with what you're trying to do.

您可以创建一个新的函数，该函数将现有的功能封装在您正在尝试做的事情中。

var WindowDialog = new function() {
    this.openedWindows = {};

    this.open = function(instanceName) {
        var handle = window.open(Array.prototype.splice.call(arguments, 1));

        this.openedWindows[instanceName] = handle;

        return handle;
    };

    this.close = function(instanceName) {
        if(this.openedWindows[instanceName])
            this.openedWindows[instanceName].close();
    };

    this.closeAll = function() {
        for(var dialog in this.openedWindows)
            this.openedWindows[dialog].close();
    };
};

Sample Usage

示例使用

WindowDialog.open('windowName', /* arguments you would call in window.open() */);
WindowDialog.open('anotherName', /* ... */);
WindowDialog.open('uniqueWindow', /* ... */);
WindowDialog.open('testingAgain', /* ... */);
WindowDialog.open('finalWindow', /* ... */);

// closes the instance you created with the name 'testingAgain'
WindowDialog.close('testingAgain');

// close all dialogs
WindowDialog.closeAll();

#2

try this to open and close

尝试打开和关闭这个

document.MyActiveWindows= new Array;

function openWindow(sUrl,sName,sProps){
document.MyActiveWindows.push(window.open(sUrl,sName,sProps))
}

function closeAllWindows(){
for(var i = 0;i < document.MyActiveWindows.length; i++)
document.MyActiveWindows[i].close()
}

#1