我如何将int链接到字符串数组java中的字符串

im writing a program where I have to have the computer randomly choose 1 of 10 objects that i have written down as a string array... im using the the math.random function to come up with a number...

即时编写一个程序,我必须让计算机随机选择10个对象中的一个,我已经写下来作为一个字符串数组...我使用math.random函数得出一个数字...

int targetNumber = (int) (Math.random() * 10);
System.out.println("I'm thinking of an item, I will only choose one of 10...");

how do i link that randomly generated int to a string inside a string array with ten different items inside... first time doing java and a pretty big noob, keep failing at this part

我如何将随机生成的int链接到一个字符串数组中的字符串,里面有十个不同的项目...第一次做java和一个相当大的菜鸟,在这部分继续失败

public static String getElement(int x){ 

    String[] stringArray = new String[10];

        stringArray[0] = "Gold";
        stringArray[1] = "Barnacle";
        stringArray[2] = "Wenches";
        stringArray[3] = "Wooden Leg";
        stringArray[4] = "Davey Jones Locker";
        stringArray[5] = "Keira Knightley";
        stringArray[6] = "Capt. Sparrow's Sword";
        stringArray[7] = "The Black Pearl";
        stringArray[8] = "Davey Jones Heart";
        stringArray[9] = "Diamonds";

    return stringArray[x];
}

its pirates of the caribean themed... school work

它的海盗以caribean为主题......学校工作

3 个解决方案

#1

With the code you posted, you can just do:

使用您发布的代码,您可以:

int targetNumber = (int) (Math.random() * 10);
System.out.println("I'm thinking of an item, I will only choose one of 10...");
System.out.println(getElement(targetNumber));

#2

You want to select one of the Strings. This is done by addressing the String array's index. Target number will generate that index, so what you do is stringArray[targetNumber]. This will return the String at the designated index.

您想要选择其中一个字符串。这是通过寻址String数组的索引来完成的。目标号码将生成该索引,因此您所做的是stringArray [targetNumber]。这将返回指定索引处的String。

If targetNumber is 3, "Wooden leg" will be selected.

如果targetNumber为3,将选择“Wooden leg”。

Try it with System.out.println(getElement(targetNumber));

尝试使用System.out.println(getElement(targetNumber));

Hope that helps.

希望有所帮助。

#3

You can use stringArray[targetNumber] to get the string "pointed to" by the random number.

您可以使用stringArray [targetNumber]来获取随机数字符串“指向”的字符串。

#1