如何查看Java 1.4中另一个字符串中是否存在子字符串？

How can I tell if the substring "template" (for example) exists inside a String object?

如何判断字符串对象中是否存在子字符串“template”(例如)?

It would be great if it was not a case-sensitive check.

如果它不是一个区分大小写的检查,那就太好了。

4 个解决方案

#1

Use a regular expression and mark it as case insensitive:

使用正则表达式并将其标记为不区分大小写:

if (myStr.matches("(?i).*template.*")) {
  // whatever
}

The (?i) turns on case insensitivity and the .* at each end of the search term match any surrounding characters (since String.matches works on the entire string).

(?i)打开不区分大小写,搜索项每端的。*匹配任何周围的字符(因为String.matches适用于整个字符串)。

#2

String.indexOf(String)

For a case insensitive search, to toUpperCase or toLowerCase on both the original string and the substring before the indexOf

对于不区分大小写的搜索,在indexOf之前的原始字符串和子字符串上的toUpperCase或toLowerCase

String full = "my template string";
String sub = "Template";
boolean fullContainsSub = full.toUpperCase().indexOf(sub.toUpperCase()) != -1;

#3

You can use indexOf() and toLowerCase() to do case-insensitive tests for substrings.

您可以使用indexOf()和toLowerCase()对子字符串执行不区分大小写的测试。

String string = "testword";
boolean containsTemplate = (string.toLowerCase().indexOf("template") >= 0);

#4

String word = "cat";
String text = "The cat is on the table";
Boolean found;

found = text.contains(word);

#1