Golang之json序列化(struct,int,map,slice)

时间:2021-08-18 07:06:53

老规矩,直接上代码

package main

import (
"encoding/json"
"fmt"
) //把结构体都改小写
type User struct {
UserName string `json:"user_name"` //json的tag标记
Nickname string `json:"nickname"`
Age int
Birthday string
Sex string
Email string
Phone string
} func testStruct() {
user1 := &User{
UserName: "超哥",
Nickname: "大头哥",
Age: ,
Birthday: "2008/8/8",
Sex: "男",
Email: "mahuateng@qq.com",
Phone: "",
} //开始json序列化
data, err := json.Marshal(user1)
if err != nil {
fmt.Printf("json.marshal failed,err:", err)
return
}
fmt.Printf("%s\n", string(data))
} func testInt() {
var a =
//开始json序列化
data, err := json.Marshal(a)
if err != nil {
fmt.Printf("json.marshal failed,err:", err)
return
}
fmt.Printf("%s\n", string(data)) } func testMap() {
var m map[string]interface{} //声明map
m = make(map[string]interface{}) //必须初始化map分配内存
m["username"] = "user1"
m["age"] =
m["sex"] = "man"
fmt.Println(m)
data, err := json.Marshal(m)
if err != nil {
fmt.Printf("json.marshal failed,err:", err)
return
}
fmt.Printf("%s\n", string(data)) } func testSlice() {
//定义一个slice,元素是map
var m map[string]interface{}
var s []map[string]interface{}
m = make(map[string]interface{})
m["username"] = "user1"
m["age"] =
m["sex"] = "man"
s = append(s, m)
m = make(map[string]interface{})
m["username"]="user2"
m["age"]=
m["sex"]="male"
s=append(s,m)
data, err := json.Marshal(s)
if err != nil {
fmt.Printf("json.marshal failed,err:", err)
return
}
fmt.Printf("%s\n", string(data)) }
func main() {
testStruct() //结构体的序列化
testInt()//序列化数值
testMap()//序列化map
testSlice()//序列化切片
}