c程序适用于windows上的linux上的segmantation故障

I wrote some c code on codeblocks. It works perfectly fine on Windows but gave segmantation fault on Linux. Why ?

我在codeblocks上写了一些c代码。它在Windows上完美运行但在Linux上出现了分段错误。为什么?

This is main. I used 3 libraries and opencells method calls a recursive method.

这是主要的。我使用3个库和opencells方法调用一个递归方法。

#include <stdio.h>
#include <stdlib.h>
#include <time.h>


int main(int argc , char *argv[])
{
     srand(time(NULL));
    int size=atoi(argv[1]),trial=atoi(argv[2]);      //! program basladıgında gelen argumanlar
    int i,j;                 //! dongu degişkenleri
        int **matrix = (int **)malloc(size * sizeof(int));          //!matriksin 1 boyutunu dinamik olarak yarattık
        int *counters = (int *)malloc(trial * sizeof(int));         //! buda counterları tutcagımız array

            for (i=0; i<size; i++)
                matrix[i] = (int *)malloc(size * sizeof(int)); //! 2. boyutada yarattık

         for(i=0;i<size;i++)
            for(j=0;j<size;j++)  //! matrixsi sıfırla saçma sapan degerler geliyo yoksa
                matrix[i][j]=0;

            for(i=0;i<trial;i++)
            {
                   counters[i]=opencells(matrix,size); //!Random kapı açan ve bunun sayısını donduren fonksyon
            }
            printboard(matrix,size,trial,counters); //!Output.txtye yazdır
            for (i=0; i<size; i++)
                free(matrix[i]);  //! ramden aldıgımız yerleri sal gitsin
            free(matrix);          //! bosu bosuna makinayı zorlamayalım
    return 0;
}

3 个解决方案

#1

int **matrix = (int **)malloc(size * sizeof(int));

Change: (int) to (int*)

更改:(int)到(int *)

int **matrix = (int **)malloc(size * sizeof(int*));

Because sizeof(int) and sizeof(int*) maybe different, so your program maybe crashed when access the not allocated memory.

因为sizeof(int)和sizeof(int *)可能不同,所以当访问未分配的内存时,您的程序可能会崩溃。

#2

int **matrix = (int **)malloc(size * sizeof(int)); 

Change: (int) to (int*)

更改:(int)到(int *)

int **matrix = (int **)malloc(size * sizeof(int*));

And while freeing the memory then use

在释放内存的同时使用

free(matrix[i]);
free(counters);

#3

int **matrix = (int **)malloc(size * sizeof(int));

You are allocating the wrong amount of memory here. You want sizeof(int*) but you do sizeof(int).

你在这里分配错误的内存量。你想要sizeof(int *),但你做sizeof(int)。

On windows, int and int* are both 32 bit big. On linux, this might well be different, and thus causing your program to incur a segmentation fault for accessing unallocated memory.

在Windows上,int和int *都是32位大。在linux上,这可能会有所不同,从而导致程序因访问未分配的内存而导致分段错误。