Consider:
考虑：
>>> numerator = 29
>>> denom = 1009
>>> print str(float(numerator/denom))
0.0
How do I make it return a decimal?
如何让它返回小数？
4 个解决方案
#1
26
Until version 3, Python's division operator, /, behaved like C's division operator when presented with two integer arguments: it returns an integer result that's truncated down when there would be a fractional part. See: PEP 238
在版本3之前，Python的除法运算符/在表示两个整数参数时表现得像C的除法运算符：它返回一个整数结果，当有一个小数部分时，它会被截断。见：PEP 238
>>> n = 29
>>> d = 1009
>>> print str(float(n)/d)
0.0287413280476
In Python 2 (and maybe earlier) you could use:
在Python 2中（可能更早），您可以使用：
>>> from __future__ import division
>>> n/d
0.028741328047571853
#2
8
In Python 2.x, division works like it does in C-like languages: if both arguments are integers, the result is truncated to an integer, so 29/1009 is 0. 0 as a float is 0.0. To fix it, cast to a float before dividing:
在Python 2.x中，除法与C语言类似：如果两个参数都是整数，则结果被截断为整数，因此浮点数为0.0时，29/1009为0。要修复它，在分割之前施放到浮子：
print str(float(numerator)/denominator)
In Python 3.x, the division acts more naturally, so you'll get the correct mathematical result (within floating-point error).
在Python 3.x中，除法行为更自然，因此您将获得正确的数学结果（在浮点错误内）。
#3
1
In your evaluation you are casting the result, you need to instead cast the operands.
在您的评估中，您正在转换结果，您需要转换操作数。
#4
0
print str(float(numerator)/float(denom))
#1
26
Until version 3, Python's division operator, /, behaved like C's division operator when presented with two integer arguments: it returns an integer result that's truncated down when there would be a fractional part. See: PEP 238
在版本3之前，Python的除法运算符/在表示两个整数参数时表现得像C的除法运算符：它返回一个整数结果，当有一个小数部分时，它会被截断。见：PEP 238
>>> n = 29
>>> d = 1009
>>> print str(float(n)/d)
0.0287413280476
In Python 2 (and maybe earlier) you could use:
在Python 2中（可能更早），您可以使用：
>>> from __future__ import division
>>> n/d
0.028741328047571853
#2
8
In Python 2.x, division works like it does in C-like languages: if both arguments are integers, the result is truncated to an integer, so 29/1009 is 0. 0 as a float is 0.0. To fix it, cast to a float before dividing:
在Python 2.x中，除法与C语言类似：如果两个参数都是整数，则结果被截断为整数，因此浮点数为0.0时，29/1009为0。要修复它，在分割之前施放到浮子：
print str(float(numerator)/denominator)
In Python 3.x, the division acts more naturally, so you'll get the correct mathematical result (within floating-point error).
在Python 3.x中，除法行为更自然，因此您将获得正确的数学结果（在浮点错误内）。
#3
1
In your evaluation you are casting the result, you need to instead cast the operands.
在您的评估中，您正在转换结果，您需要转换操作数。
#4
0
print str(float(numerator)/float(denom))