I need a bash line to check if java version currently installed is Oracle's or OpenJDK.
我需要一个bash行来检查当前安装的java版本是Oracle还是OpenJDK。
A one-liner by parsing the output of the java -version command:
通过解析java -version命令的输出来实现单行：
java -version
java Oracle output:
java Oracle输出：
java version "1.7.0_80"
Java(TM) SE Runtime Environment (build 1.7.0_80-b15)
Java HotSpot(TM) 64-Bit Server VM (build 24.80-b11, mixed mode)
java OpenJDK Output:
java OpenJDK输出：
java version "1.7.0_91"
OpenJDK Runtime Environment (amzn-2.6.2.2.63.amzn1-x86_64 u91-b00)
OpenJDK 64-Bit Server VM (build 24.91-b01, mixed mode)
2 个解决方案
#1
12
if [[ $(java -version 2>&1) == *"OpenJDK"* ]]; then echo ok; else echo 'not ok'; fi
#2
14
java -version 2>&1 | grep "OpenJDK Runtime" | wc -l
returns 0 if using Oracle JDK, 1 if using OpenJDK
如果使用Oracle JDK，则返回0;如果使用OpenJDK，则返回1
Bash condition:
Bash条件：
if [[ $(java -version 2>&1 | grep "OpenJDK Runtime") ]]
#1
12
if [[ $(java -version 2>&1) == *"OpenJDK"* ]]; then echo ok; else echo 'not ok'; fi
#2
14
java -version 2>&1 | grep "OpenJDK Runtime" | wc -l
returns 0 if using Oracle JDK, 1 if using OpenJDK
如果使用Oracle JDK，则返回0;如果使用OpenJDK，则返回1
Bash condition:
Bash条件：
if [[ $(java -version 2>&1 | grep "OpenJDK Runtime") ]]