使用Java重新排列文件数组内容

I have a File array where i have list of file names from a folder.

我有一个文件数组，其中我有一个文件夹中的文件名列表。

e.g.

例如

File file = new File("/path");
File[] arr = file.listFiles();

So my arr has all file names inside file path.

所以我的arr在文件路径中有所有文件名。

Say arr[folder1 , Folder2, Folder3].

说arr [folder1，Folder2，Folder3]。

Also i have a String array list which contains ( Folder3 , Folder1 , Folder2).

我还有一个String数组列表，其中包含（Folder3，Folder1，Folder2）。

I need to change the arr contents as per arrrayList order.

我需要根据arrrayList顺序更改arr内容。

(i.e) after processing my arr will have [ Folder3 , Folder1 , Folder2].

（即）处理后我的arr会有[Folder3，Folder1，Folder2]。

I need to do it because , i have to read folders based on certain hierarchy.

我需要这样做因为，我必须根据特定的层次结构读取文件夹。

am new to this please help how can i achieve it.

我是新手，请帮助我如何实现它。

2 个解决方案

#1

If you already have the folder names as a String list in the desired order, why do you use File.listFiles()?

如果您已按所需顺序将文件夹名称作为字符串列表，为什么要使用File.listFiles（）？

Just create the File objects from the names in the order they are listed, like this:

只需按照列出的顺序从名称中创建File对象，如下所示：

List< String > arrayList = Arrays.asList("Folder3", "Folder1", "Folder2");

File parent = new File("/path");
File[] arr = new File[arrayList.size()];

for ( int i = 0; i < arr.length; i++ )
    arr[i] = new File(parent, arrayList.get(i));

// Now arr will contain File objects in the order they are listed in arrayList

#2

-1

First you need to convert your array to a list using the Arrays.asList method. Then you can sort your array list using Collections.sort(yourNewArrayList):

首先，您需要使用Arrays.asList方法将数组转换为列表。然后，您可以使用Collections.sort（yourNewArrayList）对数组列表进行排序：

List<File> sortedFileArrayList = Collections.sort(Arrays.asList(new File("/path").listFiles()));

However, if you only need your array sorted without being converted to a list (as list conversion is not necessary for sorting) you can use

但是，如果您只需要对数组进行排序而不将其转换为列表（因为列表转换不需要进行排序），您可以使用

Arrays.sort(new File("/path").listFiles());

instead.

代替。

#1