SELECT * FROM TA WEHERE FName LIKE '%'%'
这样改怎么查询与更新
7 个解决方案
#1
WHERE FName LIKE '%''%'
#2
SELECT * FROM TA WEHERE charindex(FName, '''')> 0;
#3
declare @s varchar(8)
set @s = 'ni''b'
select @s where @s like '%''%'
#4
SELECT * FROM TA WEHERE charindex('''', FName)> 0;
#5
非常谢谢了
#6
like '%''%'
#7
不好意思,没有编辑器,有不少笔误,再更正一下:
SELECT * FROM TA WHERE charindex('''', FName)> 0;
SELECT * FROM TA WHERE charindex('''', FName)> 0;
#1
WHERE FName LIKE '%''%'
#2
SELECT * FROM TA WEHERE charindex(FName, '''')> 0;
#3
declare @s varchar(8)
set @s = 'ni''b'
select @s where @s like '%''%'
#4
SELECT * FROM TA WEHERE charindex('''', FName)> 0;
#5
非常谢谢了
#6
like '%''%'
#7
不好意思,没有编辑器,有不少笔误,再更正一下:
SELECT * FROM TA WHERE charindex('''', FName)> 0;
SELECT * FROM TA WHERE charindex('''', FName)> 0;