MVC不用302跳转Action,内部跳转

时间:2022-11-21 06:20:48

原理,在一个Action里面return 另一个Action出去。

 public class HomeController : Controller
{
// GET: Home
public ActionResult Index(int? id)
{
//必须要把Route里的Action改成最终的Action名字,否则造成读取CSHTML错误
ControllerContext.RouteData.Values["Action"] = "TS";
return TS(id);
//如果不确定到哪个Action,可以使用反射的方式来跳转
//return this.GetType().GetMethod("TS").Invoke(this,new object[]{id}) as ActionResult; }
public ActionResult TS(int? id)
{
ViewBag.Id = id;
return View();
}
}

如果连控制器也不确定,可以这么写

  ControllerContext.RouteData.Values["Action"] = "Index";
ControllerContext.RouteData.Values["Controller"] = "Test";
Type type = Assembly.GetExecutingAssembly().DefinedTypes.Where(t => t.Name == "TestController").FirstOrDefault();
object obj = Assembly.GetExecutingAssembly().CreateInstance(type.FullName);
return obj.GetType().GetMethod("Index").Invoke(obj, null) as ActionResult;