加入python中的字符串列表，并用引号将每个字符串包装起来

I've got:

我有:

words = ['hello', 'world', 'you', 'look', 'nice']

I want to have:

我想要:

'"hello", "world", "you", "look", "nice"'

What's the easiest way to do this with Python?

用Python做这件事最简单的方法是什么?

4 个解决方案

#1

>>> words = ['hello', 'world', 'you', 'look', 'nice']
>>> ', '.join('"{0}"'.format(w) for w in words)
'"hello", "world", "you", "look", "nice"'

#2

you may also perform a single format call

您还可以执行单个格式调用

>>> words = ['hello', 'world', 'you', 'look', 'nice']
>>> '"{0}"'.format('", "'.join(words))
'"hello", "world", "you", "look", "nice"'

Update: Some benchmarking (performed on a 2009 mbp):

更新:一些基准测试(在2009 mbp上执行):

>>> timeit.Timer("""words = ['hello', 'world', 'you', 'look', 'nice'] * 100; ', '.join('"{0}"'.format(w) for w in words)""").timeit(1000)
0.32559704780578613

>>> timeit.Timer("""words = ['hello', 'world', 'you', 'look', 'nice'] * 100; '"{}"'.format('", "'.join(words))""").timeit(1000)
0.018904924392700195

So it seems that format is actually quite expensive

所以看起来格式是非常昂贵的

Update 2: following @JCode's comment, adding a map to ensure that join will work, Python 2.7.12

更新2:遵循@JCode的注释，添加一个映射以确保join将工作，Python 2.7.12。

>>> timeit.Timer("""words = ['hello', 'world', 'you', 'look', 'nice'] * 100; ', '.join('"{0}"'.format(w) for w in words)""").timeit(1000)
0.08646488189697266

>>> timeit.Timer("""words = ['hello', 'world', 'you', 'look', 'nice'] * 100; '"{}"'.format('", "'.join(map(str, words)))""").timeit(1000)
0.04855608940124512

>>> timeit.Timer("""words = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] * 100; ', '.join('"{0}"'.format(w) for w in words)""").timeit(1000)
0.17348504066467285

>>> timeit.Timer("""words = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] * 100; '"{}"'.format('", "'.join(map(str, words)))""").timeit(1000)
0.06372308731079102

#3

You can try this :

你可以试试这个:

str(words)[1:-1]

#4

>>> ', '.join(['"%s"' % w for w in words])