i am using Django to create a user and an object when the user is created. But there is an error
我在创建用户时使用Django创建用户和对象。但是有一个错误
__init__() got an unexpected keyword argument 'user'
__init __()得到了一个意外的关键字参数'user'
when calling the register()
function in view.py. The function is:
在view.py中调用register()函数时。功能是:
def register(request):
'''signup view'''
if request.method=="POST":
form=RegisterForm(request.POST)
if form.is_valid():
username=form.cleaned_data["username"]
email=form.cleaned_data["email"]
password=form.cleaned_data["password"]
user=User.objects.create_user(username, email, password)
user.save()
return HttpResponseRedirect('/keenhome/accounts/login/')
else:
form = RegisterForm()
return render_to_response("polls/register.html", {'form':form}, context_instance=RequestContext(request))
#This is used for reinputting if failed to register
else:
form = RegisterForm()
return render_to_response("polls/register.html", {'form':form}, context_instance=RequestContext(request))
and the object class is:
对象类是:
class LivingRoom(models.Model):
'''Living Room object'''
user = models.OneToOneField(User)
def __init__(self, temp=65):
self.temp=temp
TURN_ON_OFF = (
('ON', 'On'),
('OFF', 'Off'),
)
TEMP = (
('HIGH', 'High'),
('MEDIUM', 'Medium'),
('LOW', 'Low'),
)
on_off = models.CharField(max_length=2, choices=TURN_ON_OFF)
temp = models.CharField(max_length=2, choices=TEMP)
#signal function: if a user is created, add control livingroom to the user
def create_control_livingroom(sender, instance, created, **kwargs):
if created:
LivingRoom.objects.create(user=instance)
post_save.connect(create_control_livingroom, sender=User)
The Django error page notifies the error information: user=User.objects.create_user(username, email, password)
and LivingRoom.objects.create(user=instance)
Django错误页面通知错误信息:user = User.objects.create_user(用户名,电子邮件,密码)和LivingRoom.objects.create(user = instance)
I tried to search this problem, finding some cases, but still cannot figure out how to solve it.
我试图搜索这个问题,找到一些案例,但仍然无法弄清楚如何解决它。
3 个解决方案
#1
5
You can't do
你做不到
LivingRoom.objects.create(user=instance)
because you have an init method that does NOT take user
as argument.
因为你有一个不将用户作为参数的init方法。
You want something like
你想要的东西
#signal function: if a user is created, add control livingroom to the user
def create_control_livingroom(sender, instance, created, **kwargs):
if created:
my_room = LivingRoom()
my_room.user = instance
#2
6
I got the same error.
我得到了同样的错误。
On my view I was overriding get_form_kwargs() like this:
在我看来,我是这样重写get_form_kwargs():
class UserAccountView(FormView):
form_class = UserAccountForm
success_url = '/'
template_name = 'user_account/user-account.html'
def get_form_kwargs(self):
kwargs = super(UserAccountView, self).get_form_kwargs()
kwargs.update({'user': self.request.user})
return kwargs
But on my form I failed to override the init() method. Once I did it. Problem solved
但是在我的表单上,我无法覆盖init()方法。一旦我做到了。问题解决了
class UserAccountForm(forms.Form):
first_name = forms.CharField(label='Your first name', max_length=30)
last_name = forms.CharField(label='Your last name', max_length=30)
email = forms.EmailField(max_length=75)
def __init__(self, *args, **kwargs):
user = kwargs.pop('user')
super(UserAccountForm, self).__init__(*args, **kwargs)
#3
1
LivingRoom.objects.create()
calls LivingRoom.__init__()
- as you might have noticed if you had read the traceback - passing it the same arguments. To make a long story short, a Django models.Model
subclass's initializer is best left alone, or should accept *args and **kwargs matching the model's meta fields. The correct way to provide default values for fields is in the field constructor using the default
keyword as explained in the FineManual.
LivingRoom.objects.create()调用LivingRoom .__ init __() - 您可能已经注意到,如果您已经阅读了回溯 - 传递相同的参数。简而言之,Django models.Model子类的初始化器最好不要单独使用,或者应该接受匹配模型元字段的* args和** kwargs。为字段提供默认值的正确方法是使用默认关键字在字段构造函数中,如FineManual中所述。
#1
5
You can't do
你做不到
LivingRoom.objects.create(user=instance)
because you have an init method that does NOT take user
as argument.
因为你有一个不将用户作为参数的init方法。
You want something like
你想要的东西
#signal function: if a user is created, add control livingroom to the user
def create_control_livingroom(sender, instance, created, **kwargs):
if created:
my_room = LivingRoom()
my_room.user = instance
#2
6
I got the same error.
我得到了同样的错误。
On my view I was overriding get_form_kwargs() like this:
在我看来,我是这样重写get_form_kwargs():
class UserAccountView(FormView):
form_class = UserAccountForm
success_url = '/'
template_name = 'user_account/user-account.html'
def get_form_kwargs(self):
kwargs = super(UserAccountView, self).get_form_kwargs()
kwargs.update({'user': self.request.user})
return kwargs
But on my form I failed to override the init() method. Once I did it. Problem solved
但是在我的表单上,我无法覆盖init()方法。一旦我做到了。问题解决了
class UserAccountForm(forms.Form):
first_name = forms.CharField(label='Your first name', max_length=30)
last_name = forms.CharField(label='Your last name', max_length=30)
email = forms.EmailField(max_length=75)
def __init__(self, *args, **kwargs):
user = kwargs.pop('user')
super(UserAccountForm, self).__init__(*args, **kwargs)
#3
1
LivingRoom.objects.create()
calls LivingRoom.__init__()
- as you might have noticed if you had read the traceback - passing it the same arguments. To make a long story short, a Django models.Model
subclass's initializer is best left alone, or should accept *args and **kwargs matching the model's meta fields. The correct way to provide default values for fields is in the field constructor using the default
keyword as explained in the FineManual.
LivingRoom.objects.create()调用LivingRoom .__ init __() - 您可能已经注意到,如果您已经阅读了回溯 - 传递相同的参数。简而言之,Django models.Model子类的初始化器最好不要单独使用,或者应该接受匹配模型元字段的* args和** kwargs。为字段提供默认值的正确方法是使用默认关键字在字段构造函数中,如FineManual中所述。