this is a reference from this posted question, as I am looking to rearrange the value of attribute <pos>
inside nodes <est_mat>
, so the first node of <est_mat>
will have <pos>10</pos>
, then the second <est_mat>
node will have <pos>20</pos>
and so on. I have this query from the help of one of the users from the posted reference mentioned. So, supposing the following xml structure:
这是这个问题的参考,因为我想重新排列节点
DECLARE @xml XML=
N'<flint>
<app>
<comp>59</comp>
<signal>ORDERBOOK</signal>
<sigref>000000172</sigref>
<date>20170201</date>
<time>114954</time>
<id>SFC</id>
<revision>006</revision>
<data>
<rec>
<rpos>1</rpos>
<revision>006</revision>
<order>
<type>SFC</type>
<orno />
<pono>0</pono>
<seri>GLW</seri>
<item>GEC1H-PCB-00081-01</item>
<sfc_type>BTO</sfc_type>
<revi>46</revi>
<sel_code />
<family />
<qty>300</qty>
<del_qty>0</del_qty>
<rej_qty>0</rej_qty>
<uom>ea</uom>
<clot />
<prio>999</prio>
<wh>J59MF6</wh>
<cdel_date>20170201</cdel_date>
<cdel_time>114954</cdel_time>
<prod_date>20170201</prod_date>
<prod_time>114954</prod_time>
<eff_date>20170201</eff_date>
<eff_time>114954</eff_time>
<target>0</target>
<line />
<status>Planned</status>
<skit_nr />
<pick_stat>N</pick_stat>
<so_orno />
<so_pono>0</so_pono>
<est_mats>
<est_mat>
<pos>10</pos>
<item>GEC1H-BTL-CARDBOARD-BOX</item>
<revi>A</revi>
<opno>0</opno>
<qty>0.004</qty>
<uom>ea</uom>
<wh>J59JW2</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
<est_mat>
<pos>20</pos>
<item>GEC1H-BTL-FD79-G007-00SA</item>
<revi>A-002</revi>
<opno>0</opno>
<qty>1</qty>
<uom>ea</uom>
<wh>J59WP4</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
<est_mat>
<pos>30</pos>
<item>GEC1H-ESC10-091-SOP-1017KXX</item>
<revi>NR-00</revi>
<opno>0</opno>
<qty>1.1</qty>
<uom>ea</uom>
<wh>J59WP4</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
<est_mat>
<pos>40</pos>
<item>GEC1J-LED-NFSL757DV1-835</item>
<revi>NR-00</revi>
<opno>0</opno>
<qty>9</qty>
<uom>ea</uom>
<wh>J59WP4</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
<est_mat>
<pos>10</pos>
<item>GEC1H-BTL-CARDBOARD-BOX</item>
<revi>A</revi>
<opno>0</opno>
<qty>0.004</qty>
<uom>ea</uom>
<wh>J59WP4</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
<est_mat>
<pos>20</pos>
<item>GEC1H-BTL-FD79-G007-00SA</item>
<revi>A-002</revi>
<opno>0</opno>
<qty>1</qty>
<uom>ea</uom>
<wh>J59WP4</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
<est_mat>
<pos>30</pos>
<item>GEC1H-ESC10-091-SOP-1017KXX</item>
<revi>NR-00</revi>
<opno>0</opno>
<qty>1.1</qty>
<uom>ea</uom>
<wh>J59WP4</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
<est_mat>
<pos>40</pos>
<item>GEC1J-LED-NFSL757DV1-835</item>
<revi>NR-00</revi>
<opno>0</opno>
<qty>9</qty>
<uom>ea</uom>
<wh>J59WP4</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
<est_mat>
<pos>40</pos>
<item>GEC1J-LED-NFSL757DV1-835</item>
<revi>NR-00</revi>
<opno>0</opno>
<qty>9</qty>
<uom>ea</uom>
<wh>J59WP4</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
<est_mat>
<pos>40</pos>
<item>TESTING2</item>
<revi>46</revi>
<opno>0</opno>
<qty>0.04</qty>
<uom>ea</uom>
<wh>J59JW2</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
<est_mat>
<pos>10</pos>
<item>TESTING</item>
<revi>46</revi>
<opno>0</opno>
<qty>3</qty>
<uom>ea</uom>
<wh>J59JW2</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
<est_mat>
<pos>20</pos>
<item>GEC1J-SW3576L11</item>
<revi>46</revi>
<opno>0</opno>
<qty>3</qty>
<uom>ea</uom>
<wh>J59JW2</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
<est_mat>
<pos>30</pos>
<item>GEC1J-SW359EL11</item>
<revi>46</revi>
<opno>0</opno>
<qty>3</qty>
<uom>ea</uom>
<wh>J59JW2</wh>
<backflush>Y</backflush>
<rpl_method />
<point_of_usage />
</est_mat>
</est_mats>
</order>
</rec>
</data>
</app>
</flint>';
and this query:
而这个查询:
SELECT @xml.query(N'/flint/*[local-name()!="est_mats"]') AS [*]
,(
SELECT ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) * 10 AS pos
,em.value(N'item[1]',N'nvarchar(max)') AS item
,em.value(N'qty[1]',N'decimal(16,4)') AS qty
FROM @xml.nodes(N'flint/app/data/rec/order/est_mats/est_mat') AS A(em)
FOR XML PATH('est_mat'),ROOT('est_mats'),TYPE
)
FOR XML PATH(N'flint');
How can I generate the structure again by having that attribute <pos>
being ordered as explained above ?
如何通过如上所述对
At the moment the query throws the same xml structure without changing the value of <pos>
此时查询将抛出相同的xml结构而不更改
1 个解决方案
#1
1
You might try it like this:
您可以这样尝试:
First your (reduced!) sample data with silly values in <pos>
to demonstrate the solution:
首先在
DECLARE @xml XML=
N'<flint>
<app>
<comp>59</comp>
<!--more elements-->
<revision>006</revision>
<data>
<rec>
<rpos>1</rpos>
<revision>006</revision>
<order>
<type>SFC</type>
<!--more elements-->
<so_pono>0</so_pono>
<est_mats>
<est_mat>
<pos>999</pos>
<item>GEC1H-BTL-CARDBOARD-BOX</item>
<!--more elements-->
</est_mat>
<est_mat>
<pos>333</pos>
<item>GEC1H-BTL-FD79-G007-00SA</item>
<!--more elements-->
</est_mat>
</est_mats>
</order>
</rec>
</data>
</app>
</flint>';
--No we read the re-numbered <est_mats>
into a staging variable
- 我们没有将重新编号的
DECLARE @est_mats XML=
(
SELECT ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) * 10 AS pos
,em.value(N'item[1]',N'nvarchar(max)') AS item
--add more elements here
FROM @xml.nodes(N'flint/app/data/rec/order/est_mats/est_mat') AS A(em)
FOR XML PATH('est_mat'),ROOT('est_mats'),TYPE
);
--Now we remove the existing <est_mats>
completely
- 现在我们完全删除现有的
SET @xml.modify(N'delete (flint/app/data/rec/order/est_mats)[1]');
--Just to insert the modified part in the former place
- 只需将修改后的部件插入以前的位置即可
SET @xml.modify(N'insert sql:variable("@est_mats") as last into (flint/app/data/rec/order)[1]');
--This is the result
- 这是结果
SELECT @xml;
<flint>
<app>
<comp>59</comp>
<!--more elements-->
<revision>006</revision>
<data>
<rec>
<rpos>1</rpos>
<revision>006</revision>
<order>
<type>SFC</type>
<!--more elements-->
<so_pono>0</so_pono>
<est_mats>
<est_mat>
<pos>10</pos>
<item>GEC1H-BTL-CARDBOARD-BOX</item>
</est_mat>
<est_mat>
<pos>20</pos>
<item>GEC1H-BTL-FD79-G007-00SA</item>
</est_mat>
</est_mats>
</order>
</rec>
</data>
</app>
</flint>
#1
1
You might try it like this:
您可以这样尝试:
First your (reduced!) sample data with silly values in <pos>
to demonstrate the solution:
首先在
DECLARE @xml XML=
N'<flint>
<app>
<comp>59</comp>
<!--more elements-->
<revision>006</revision>
<data>
<rec>
<rpos>1</rpos>
<revision>006</revision>
<order>
<type>SFC</type>
<!--more elements-->
<so_pono>0</so_pono>
<est_mats>
<est_mat>
<pos>999</pos>
<item>GEC1H-BTL-CARDBOARD-BOX</item>
<!--more elements-->
</est_mat>
<est_mat>
<pos>333</pos>
<item>GEC1H-BTL-FD79-G007-00SA</item>
<!--more elements-->
</est_mat>
</est_mats>
</order>
</rec>
</data>
</app>
</flint>';
--No we read the re-numbered <est_mats>
into a staging variable
- 我们没有将重新编号的
DECLARE @est_mats XML=
(
SELECT ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) * 10 AS pos
,em.value(N'item[1]',N'nvarchar(max)') AS item
--add more elements here
FROM @xml.nodes(N'flint/app/data/rec/order/est_mats/est_mat') AS A(em)
FOR XML PATH('est_mat'),ROOT('est_mats'),TYPE
);
--Now we remove the existing <est_mats>
completely
- 现在我们完全删除现有的
SET @xml.modify(N'delete (flint/app/data/rec/order/est_mats)[1]');
--Just to insert the modified part in the former place
- 只需将修改后的部件插入以前的位置即可
SET @xml.modify(N'insert sql:variable("@est_mats") as last into (flint/app/data/rec/order)[1]');
--This is the result
- 这是结果
SELECT @xml;
<flint>
<app>
<comp>59</comp>
<!--more elements-->
<revision>006</revision>
<data>
<rec>
<rpos>1</rpos>
<revision>006</revision>
<order>
<type>SFC</type>
<!--more elements-->
<so_pono>0</so_pono>
<est_mats>
<est_mat>
<pos>10</pos>
<item>GEC1H-BTL-CARDBOARD-BOX</item>
</est_mat>
<est_mat>
<pos>20</pos>
<item>GEC1H-BTL-FD79-G007-00SA</item>
</est_mat>
</est_mats>
</order>
</rec>
</data>
</app>
</flint>