在windows下用Flask实现图片上传,上传后总是找不到正确的文件夹路径。修改上传文件夹为如下的时候:
<span style="font-size:18px;">UPLOAD_FOLDER =</span>sys.path[0]
上传到程序所在的当前文件夹,但是添加了当前路径下的文件夹后就会出错,试过了各种组合,最后找到了一个很好的并且可以随意任何操作系统之间迁移的方法:
python中os.path常用模块:os.path.sep路径分隔符 ,linux下就用这个了’/’os.path.altsep:
根目录:os.path.curdir
当前目录:os.path.pardir
父目录:os.path.abspath(path)
绝对路径:os.path.join()
常用来链接路径:os.path.split(path),把path分为目录和文件两个部分,以列表返回
修改后程序如下图:
import sys reload(sys) sys.setdefaultencoding("utf-8") //设置默认编码为UTF-8可以正常显示中文 import os from flask import Flask, request, redirect, url_for from werkzeug import secure_filename from flask import send_from_directory import os.path UPLOAD_FOLDER =os.path.curdir+os.path.sep+'tmp'+os.path.sep //该路径为当前文件夹拼接windows下文件分隔符再拼接‘tmp'文件夹,再拼接文件分隔符 ALLOWED_EXTENSIONS = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif']) //允许上传的图片类型 app = Flask(__name__) app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER def allowed_file(filename): return '.' in filename and \ filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS @app.route('/', methods=['GET', 'POST']) def upload_file(): if request.method == 'POST': file = request.files['file'] if file and allowed_file(file.filename): filename = secure_filename(file.filename) file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename)) return redirect(url_for('uploaded_file', filename=filename)) return ''' <!doctype html> <title>Upload new File</title> <h1>Upload new File</h1> <form action="" method=post enctype=multipart/form-data> <!--只要确保你没忘记在 HTML 表单中设置<tt class="docutils literal"><span class="pre">enctype="multipart/form-data"</span></tt> 属性,不然你的浏览器根本不会发送文件。--> <p><input type=file name=file> <input type=submit value=Upload> </form> ''' @app.route('/uploads/<filename>') def uploaded_file(filename): return send_from_directory(app.config['UPLOAD_FOLDER'],filename) if __name__=='__main__': app.run(debug=True) 1.只要确保你没忘记在 HTML 表单中设置<tt class="docutils literal"><span class="pre">enctype="multipart/form-data"</span></tt> 属性,不然你的浏览器根本不会发送文件。