HDU 3790 最短路径问题

用的spfa的思想写的，我感觉用一个标记数组flag[]来标志是否在队列中，好像不是很有用啊，只要做了松弛操作，我感觉都应该入队才是吧= =。这道题目就是更新路径的时候顺便更新一下花费。

#include <cstdio>
#include <iostream>
#include <cstring>
#include <queue>
#include <vector>

using namespace std;
const int INF = 0x3f3f3f;
const int MAX = 1e3 + 5;
int d[MAX], p[MAX];//, flag[MAX];
struct EDGE
{
    int to, cost, price;
    EDGE(int a = 0, int b = 0, int c = 0)
    : to(a), cost(b), price(c)
    {}
};
vector<EDGE> que[MAX];
queue<int> coor;

int main()
{
    int n, m;
    while (scanf("%d%d", &n, &m))
    {
        if (n == 0 && m == 0)
        {
            break;
        }
        for (int i = 1; i <= n; ++i)
            que[i].clear();
        int t_from, t_to, t_cost, t_price;
        //memset(flag, 0, sizeof(flag));
        memset(d, INF, sizeof(d));
        memset(p, INF, sizeof(p));
        for (int i = 0; i < m; ++i)
        {
            scanf("%d%d%d%d", &t_from, &t_to, &t_cost, &t_price);
            que[t_from].push_back(EDGE(t_to, t_cost, t_price));
            que[t_to].push_back(EDGE(t_from, t_cost, t_price));
        }
        int st, ed;
        scanf("%d%d", &st, &ed);
       // flag[st] = 1;
        d[st] = 0;
        p[st] = 0;
        coor.push(st);
        int res = INF;
        while (!coor.empty())
        {
            int t_coor = coor.front();
            coor.pop();
            //flag[t_coor] = 0;
            int lenth = que[t_coor].size();
            for (int i = 0; i < lenth; ++i)
            {
                EDGE t_edge = que[t_coor][i];
                if (d[t_edge.to] > d[t_coor] + t_edge.cost)
                {
                    d[t_edge.to] = d[t_coor] + t_edge.cost;
                   // printf("from(%d) to(%d)\n", t_coor, t_edge.to);
                   // printf("shortest path = %d price = %d\n", d[ed], p[ed]);
                  //  if (p[t_edge.to] >= p[t_coor] + t_edge.price)
                    p[t_edge.to] = p[t_coor] + t_edge.price;
                    //printf("now price = %d\n", p[ed]);
                   // res = min(res, p[ed]);
                    coor.push(t_edge.to);
                }
                else if (d[t_edge.to] == d[t_coor] + t_edge.cost && p[t_edge.to] > p[t_coor] + t_edge.price)
                    p[t_edge.to] = p[t_coor] + t_edge.price;
            }
        }
        printf("%d %d\n", d[ed], p[ed]);
    }

    return 0;
}