https://www.cnblogs.com/evablogs/p/6754981.html
题目：输入某年某月某日，判断这一天是这一年的第几天？
程序分析：
月份天数：
| 月份 | 天数 |
| 2 | 平年28天，闰年29天 |
| 1,3,5,7,8,10,12 | 31 |
| 4,6,9,11 | 30 |
闰年：
1、非整百年：能被4整除的为闰年。（如2004年就是闰年,2100年不是闰年）
2、整百年：能被400整除的是闰年。(如2000年是闰年，1900年不是闰年)
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>>> L=[31,31,30,31,30,31,31,30,31,30,31]
>>> def caldate(a,b,c):
s=0
if(a%100!=0 and a%4==0 or a%100==0 and a%400==0):
L.insert(1,29)
else:
L.insert(1,28)
for i in range(b-1):
s=s+L[i]
return s+c
>>> caldate(2016,1,2)
2>>> caldate(2016,3,2)
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改进版：考虑了月份和天数的有效性（哈哈，对比网上的答案，一看自己的代码就像是菜鸟级的，还有很多需要学习的地方）
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def caldate(a,b,c):
L=[31,31,30,31,30,31,31,30,31,30,31]
s=0
Leap=0
if(a%100!=0 and a%4==0 or a%100==0 and a%400==0):
L.insert(1,29)
Leap=1
else:
L.insert(1,28)
if 0<b<=12:
if 0<c<=31:
if((b==2)and(Leap==1)and(c<=29)or((b==2)and(Leap==0)and(c<=28))):
for i in range(b-1):
s=s+L[i]
return s+c
else:
print 'The February should not greater than 28 or 29'
else:
print 'The date is error'
else:
print 'The month is invalid'
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输出：
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>>> caldate(2016,4,33)
The date is error
>>> caldate(2017,2,30)
The February should not greater than 28 or 29
>>> caldate(2017,2,28)
59>>> caldate(2017,2,29)
The February should not greater than 28 or 29
>>> caldate(2017,13,29)
The month is invalid
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网上答案：
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#!/usr/bin/python# -*- coding: UTF-8 -*- year = int(raw_input('year:\n'))
month = int(raw_input('month:\n'))
day = int(raw_input('day:\n'))
months = (0,31,59,90,120,151,181,212,243,273,304,334)
if 0 < month <= 12:
sum = months[month - 1]
else:
print 'data error'
sum += day
leap = 0
if (year % 400 == 0) or ((year % 4 == 0) and (year % 100 != 0)):
leap = 1
if (leap == 1) and (month > 2):
sum += 1
print 'it is the %dth day.' % sum
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输出结果：
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year:2015month:6day:7it is the 158th day.
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