1.写生成器,从文件中读取内容,再每一行读取的内容前加上 ‘***’之后返回给用户 def func(filename):
word = input('输入你想找的内容:')
with open(filename,mode='r',encoding='utf-8') as f:
for line in f:
if word in line:
yield line file = input('输入你要查找的文件:')
g = func(file)
for i in g:
print('###'+ i.strip())
2.面试题
def demo():
for i in range(4):
yield i g=demo() g1=(i for i in g)
g2=(i for i in g1)
print(list(g1))
print(list(g2))
[0, 1, 2, 3]
[]
看这个,我觉得例2可能更贴切于生成器,类似于篮子装东西,取完值则不可再取。
例2:
def demo():
for i in range(4):
yield i g=demo() g1=(i for i in g)
g2=(i for i in g) print(list(g1))
print(list(g2))
[0, 1, 2, 3]
[]
3面试题:
def add(n,i):
return n+i def test():
for i in range(4):
yield i g=test()
for n in [1,10]:
g=(add(n,i) for i in g) print(list(g))
分析:
for n in [1,10]:
g=(add(n,i) for i in g) n = 1
g = (add(n,i) for i in g)
n = 10
g = (add(n,i) for i in g) n = 1的表达式 g 赋值给了n=10的g的表达式,g = test()==(0,1,2,3)
n = 1的时候,其下面的表达式并没有被执行调用,等print(list(g))的时候开始调用n=10下面的表达式。
n = 10
g = (add(n,i) for i in (add(n,i) for i in g))
g = (add(n,i) for i in (11,12,13,14))
g = (21,22,23,24)