I have a program that outputs to file an unevenly spaced time series of vectors (one vector per interval) that vary in size . I'm wondering what would be the best way of formatting the output so that the file can be read into a list of vectors in R (Assuming that is the correct data structure), and what code in R i would use to read it.
我有一个程序,它输出一个不均匀间隔的向量时间序列(每间隔一个向量),它们的大小不同。我想知道格式化输出的最好方式是什么,这样文件就可以被读入R中的向量列表(假设这是正确的数据结构),以及我将使用R中的哪些代码来读取它。
For example, I imagine the output could look something like this:
例如,我认为输出可以是这样的:
1, 24, 5, 211
3, 5
59, 465, 3, 333, 9, 98
or
或
(1 24 5 211)
(3 5)
(59 465 3 333 9 98)
But what I'm saying is that I want to change the formatting to suite the R read function.
但我想说的是,我想要改变格式,以使R读函数。
1 个解决方案
#1
0
Keep fill = TRUE
保持填补= TRUE
data = read.table(file.choose(),sep=",",fill=TRUE)
data[is.na(data)] <- "" # Replacing NA Values with nothing..
#1
0
Keep fill = TRUE
保持填补= TRUE
data = read.table(file.choose(),sep=",",fill=TRUE)
data[is.na(data)] <- "" # Replacing NA Values with nothing..