模式，中值，均值，标准差，方差计算器。

Trying to write this small program to help me in my Stats class, everything seems to be calculating accordingly except for the Median. What am i missing?

试着编写这个小程序来帮助我的Stats类，一切似乎都在计算，除了中值。我缺少什么?

Extra Credit if anyone is willing to do the Variance function for me as well x).

如果有人愿意为我做这个方差函数。

Running OSX with the GCC compiler.

使用GCC编译器运行OSX。

#include<stdio.h>  
#include<math.h>   

float mean1(float[],int);  
float median1(float[],int);  
float mode1(float[],int);  
double standarddeviation1(float[],int);  

int main()  
{  
int i,n,choice;  
float array[100],mean,median,mode;  
double standarddeviation;  

printf("Enter No of Elements\n");  
   scanf("%d",&n);  
printf("Enter Elements\n");  

for(i=0;i<=n-1;i++)  
    scanf("%f",&array[i]);  
do  
{  
    printf("\n\tEnter Choice\n\t1.Mean\n\t2.Median\n\t3.Mode\n\t4.Standard deviation\n\t5.Exit\n");  
    scanf("%d",&choice);  

    switch(choice)  
    {  
        case 1: mean=mean1(array,n);  
            printf("\n\tMean = %f\n",mean);  
            break;  
        case 2: median=median1(array,n);  
            printf("\n\tMedian = \n",median);  
            break;  
        case 3: mode=mode1(array,n);  
            printf("\n\tMode = %f\n",mode);  
            break;   
        case 4: standarddeviation=standarddeviation1(array,n);  
            printf("\n\tStandard deviation = %f\n",standarddeviation); 
            break;  
        case 5: break;  
        default:printf("Wrong Option");  
            break;  
    }  

}while(choice!=5);  
  getchar(); 

return 0;  
}  

float mean1(float array[],int n) {  
    int i;  
    float sum=0;  
    for(i=0;i<=n;i++)  
    sum=sum+array[i];  
return (sum/n);  
}  
float median1(float array[],int n) {  
float temp;  
int i,j;  
for(i=n-1;i>=0;i--)  
    for(j=0;j<=i;j++)  
        if(array[j]>=array[j+1])  
        {  
            temp=array[j];  
            array[j]=array[j+1];  
            array[j+1]=temp;  
        }  

if(n%2==0)  
    return (array[n/2]+array[n/2-1])/2;  
else  
    return array[n/2];  
}  
float mode1(float array[],int n) {  
return (3*median1(array,n)-2*mean1(array,n));  
}  
double standarddeviation1(float array[],int n) {  
int j;   
double max[100],sum,variance,mean;  
mean=mean1(array,n);  
sum=0;  
for(j=0;j<=n;j++)   
{  
    max[j]=pow((array[j]-mean),2);  
    sum+=max[j];  
}  
variance=sum/(j-1);   
return sqrt(variance);  
}

1 个解决方案

#1

Your mean1 isn't correct either. Both errors have the same reason, you access an element past the assigned number n

你的意思也不正确。这两个错误都有相同的原因，您可以访问被分配的编号n的元素。

float mean1(float array[],int n) {  
    int i;  
    float sum=0;  
    for(i=0;i<=n;i++)  
    sum=sum+array[i];  
return (sum/n);  
}

You are adding n+1 elements here but divide by n. The n+1st element doesn't belong in the calculation. Make the loop condition i < n.

你在这里加n+1个元素但是除以n, n+1元素不属于计算。使循环条件i < n。

float median1(float array[],int n) {  
float temp;  
int i,j;  
for(i=n-1;i>=0;i--)  
    for(j=0;j<=i;j++)

In your bubble sort, you access array[n] too, which has an arbitrary value (and if n == 100 is past the allocated array, hence causes undefined behaviour). Make the inner loop condition j < i or start the outer loop with i = n-2.

在您的冒号排序中，也可以访问数组[n]，它具有任意的值(如果n == 100，则是经过分配的数组，从而导致未定义的行为)。使内循环条件为j < i或以i = n-2启动外部循环。

In standarddeviation1 you overstep the array bounds too.

在标准偏差中，你也超出了数组的界限。

#1