计算字符串中字符的出现次数

In XSLT 1.0, I have a node with values having special characters, numbers, alphabets. From this , I need to take the count of a particular character. Consider the below node.

在XSLT 1.0中，我有一个节点，其值包含特殊字符，数字，字母。由此，我需要计算一个特定的角色。考虑以下节点。

<sample>abc.123.@#$,def$%^123.kl.lo</sample>

In this, I need to get the count of decimal points alone. So, the result should be 4. Please put your thoughts. Below are few codes that I tried.

在这里，我需要单独得到小数点数。所以，结果应该是4.请把你的想法。以下是我尝试过的几个代码。

<xsl:value-of select="count(/*/*/sample[contains(., '.')]) "/>

<xsl:value-of select="count(//sample[.])"/>

1 个解决方案

#1

Check this code your problem solve

检查此代码您的问题解决

string-length(//sample) - string-length(translate(//sample, '.', ''))