I was wondering if it is possible to plot a line of the form y = mx+b in Matlab? I used polyfit to get a 1x2 array that contains the slope and intercept.
我想知道是否可以在Matlab中画出y = mx+b的直线?我使用了polyfit来得到一个包含斜率和截距的1x2数组。
Here is what I have so far:
以下是我目前所拥有的:
lineFit = polyfit(tauBin, a5array, 1);
plot((lineFit(1)*x + lineFit(2)))
How can I plot this?
怎么画呢?
2 个解决方案
#1
#2
4
There is REFLINE function in Statistical Toolbox. Probably the easiest for your task:
统计工具箱中有回流函数。可能对你的任务最简单:
refline(m,b)
or if you want to change line properties:
或者如果你想改变线路属性:
hr = refline(m,b);
set(hr,'Color','r')
It uses limits from the current axes. So if you change the limits later, it probably would be easier to delete it (delete(hr)) and draw again.
它利用了当前轴的极限。因此，如果您稍后更改限制，可能会更容易删除它(删除(hr))并再次绘制。
#1
13
There are two way that immediately come to mind. The first is with FPLOT:
有两种方法立刻浮现在脑海中。第一个是FPLOT:
>> m = 2; b = 1; >> fplot(@(x)m*x+b, [0 10]);
The second is to calculate the y values directly in the call to the PLOT command:
第二种方法是在调用PLOT命令时直接计算y值:
>> m = 2; b = 1; x = 1:10; >> plot(x, m*x+b);
#2
4
There is REFLINE function in Statistical Toolbox. Probably the easiest for your task:
统计工具箱中有回流函数。可能对你的任务最简单:
refline(m,b)
or if you want to change line properties:
或者如果你想改变线路属性:
hr = refline(m,b);
set(hr,'Color','r')
It uses limits from the current axes. So if you change the limits later, it probably would be easier to delete it (delete(hr)) and draw again.
它利用了当前轴的极限。因此，如果您稍后更改限制，可能会更容易删除它(删除(hr))并再次绘制。