How can I grab the entire content inside <body> tag with regex?
如何使用正则表达式获取标记内的整个内容？
For instance,
例如，
<html><body><p><a href="#">xx</a></p>
<p><a href="#">xx</a></p></body></html>
I want to return this only,
我只想归还这个，
<p><a href="#">xx</a></p>
<p><a href="#">xx</a></p>
Or any other better ideas? maybe DOM but I have to use saveHTML(); then it will return doctype and body tag...
还是其他更好的想法？也许DOM，但我必须使用saveHTML（）;那么它将返回doctype和body标签......
HTML Purifier is a pain to use so I decide not to use it. I thought regex could be the next best option for my disaster.
HTML Purifier很难用，所以我决定不使用它。我认为正则表达式可能是我灾难的下一个最佳选择。
2 个解决方案
#1
21
preg_match("/<body[^>]*>(.*?)<\/body>/is", $html, $matches);
$matches[1] will be the contents of the body tag
$ matches [1]将是body标签的内容
#2
1
preg_match("~<body.*?>(.*?)<\/body>~is", $html, $match);
print_r($match);
#1
21
preg_match("/<body[^>]*>(.*?)<\/body>/is", $html, $matches);
$matches[1] will be the contents of the body tag
$ matches [1]将是body标签的内容
#2
1
preg_match("~<body.*?>(.*?)<\/body>~is", $html, $match);
print_r($match);