不兼容整数到指针的转换，从'int'分配到'int *'

I have yet another pesky warning I would like gone. Basically, I have an int declared like this: @property (nonatomic, assign) int *myInt; and set like this: myInt = 0;. It is also synthesized in the implementation file. I am getting a warning on the line where I set the int's value and it says Incompatible intiger to pointer conversion assigning to 'int *' from 'int'. What should I do to fix this?

我还有另一个讨厌的警告想要离开。基本上，我有一个int类型声明如下:@property (nonatomic, assign) int *myInt;设为:myInt = 0;它也在实现文件中被合成。在我设置int值的行上，我得到了一个警告，它表示不兼容的intiger指针转换为“int *”，从“int”到“int”。我该怎么解决这个问题呢?

4 个解决方案

#1

There's a big hint in the error message!

错误消息中有一个很大的提示!

In C and Objective C, an int is a primitive data type. You've written int *, which means "a pointer to an int", whereas it looks like you just wanted an int.

在C和Objective C中，int是一种原始数据类型。你已经写了int *，它的意思是“指向int的指针”，而看起来你只是想要一个int。

So change your property to this:

所以把你的财产换成这个:

@property (nonatomic, assign) int myInt;

For more info, google "C pointers" and you'll find information like this: http://pw1.netcom.com/~tjensen/ptr/pointers.htm

对于更多的信息，谷歌“C指针”，你会找到这样的信息:http://pw1.netcom/ ~tjensen/ptr/pointers.htm。

#2

Yes, simply remove asterisk (*) from declaration.

是的，只需从声明中删除星号(*)。

for example.declare BOOL isChecked instead of BOOL * isChecked.

例如，声明BOOL被检查，而不是BOOL *被检查。

#3

Another way to resolve this is to simply not declare a pointer (drop the asterisk):

解决这个问题的另一种方法是简单地不声明指针(删除星号):

@interface ViewController : UIViewController {
    NSUInteger myObjcInt;  // unsigned ( >= 0 ) NSObject int, yo
}

#4

int *MyInt is a pointer to int, not an int.
As others told you, just remove the * and you will have a regular int.

int *MyInt是一个指向int的指针，而不是int.正如其他人告诉你的，只要删除*，就会有一个常规的int。

#1