贪心一下。有k次机会,也就是那些数字中,最大的k-1可以不选择。答案为:sum{a[i]}-sum{最大的k-1个a[i]}+n。注意:k>=n的时候直接输出n。
#pragma comment(linker, "/STACK:1024000000,1024000000")
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<vector>
#include<map>
#include<set>
#include<queue>
#include<stack>
#include<iostream>
using namespace std;
typedef long long LL;
const double pi=acos(-1.0),eps=1e-;
void File()
{
freopen("D:\\in.txt","r",stdin);
freopen("D:\\out.txt","w",stdout);
}
inline int read()
{
char c = getchar(); while(!isdigit(c)) c = getchar();
int x = ;
while(isdigit(c)) { x = x * + c - ''; c = getchar(); }
return x;
} const int maxn=+;
int T,n,k;
LL a[maxn],ans;
struct X{int p; LL val;}s[maxn];
bool cmp(X a,X b){ return a.val>b.val; } int main()
{
scanf("%d",&T);
while(T--)
{
scanf("%d%d",&n,&k); ans=;
for(int i=;i<=n-;i++) scanf("%lld",&a[i]);
if(k>=n) { printf("%d\n",n); continue; }
sort(a+,a+n);
for(int i=;i<=n-k;i++) ans=ans+a[i]; ans=ans+n;
printf("%lld\n",ans);
}
return ;
}