I have a string constant defined like this:
我有一个像这样定义的字符串常量：
#define kMyString @"This is my string text!";
Somewhere in the code I would like to print-out this piece of code with NSLog like that:
代码中的某处我想用NSLog打印出这段代码：
NSLog(@"This is it: %@",kMyString);
But get a build error: Expected expression.
但得到一个构建错误：预期的表达式。
I have already looked at the Apple's Format Specifiers but could not figured it out.
我已经查看了Apple的格式说明符，但无法弄明白。
Can someone please explain it to me how to do this?
有人可以向我解释如何做到这一点？
Thanks!
谢谢！
3 个解决方案
#1
37
You should remove ; from the definition of kMyString:
你应该删除;从kMyString的定义：
#define kMyString @"This is my string text!"
The way you did it is equivalent to:
你这样做的方式相当于：
NSLog(@"This is it: %@", @"This is my string text!";);
#2
2
Remove that semi colon after #define and use %@ and it will work.
在#define之后删除该半冒号并使用％@，它将起作用。
#3
2
%@ is for objects. BOOL is not an object.
On the bases of data type %@ changes as follows
％@用于对象。 BOOL不是一个对象。在数据类型％@的基础上改变如下
For Strings you use %@
For int you use %i
For float you use %f
For double you use %lf
#1
37
You should remove ; from the definition of kMyString:
你应该删除;从kMyString的定义：
#define kMyString @"This is my string text!"
The way you did it is equivalent to:
你这样做的方式相当于：
NSLog(@"This is it: %@", @"This is my string text!";);
#2
2
Remove that semi colon after #define and use %@ and it will work.
在#define之后删除该半冒号并使用％@，它将起作用。
#3
2
%@ is for objects. BOOL is not an object.
On the bases of data type %@ changes as follows
％@用于对象。 BOOL不是一个对象。在数据类型％@的基础上改变如下
For Strings you use %@
For int you use %i
For float you use %f
For double you use %lf