malloc和realloc数组提供意外输出

When input is '1 2 3 4 5 6 7 8 9 10 11' Expected output should be the same as input. Yet the output is '1 2 3 4 5 6 7 8 9 10 -1850774484' . Only happens when there are more than 10 integers being inputted. Where did I go wrong with my realloc line

当输入为'1 2 3 4 5 6 7 8 9 10 11'时预期输出应与输入相同。然而输出是'1 2 3 4 5 6 7 8 9 10 -1850774484'。仅当输入的整数超过10时才会发生。我的realloc系列在哪里出错了

#include <stdio.h>
#include <stdlib.h>

#define INITIAL_SIZE 10

int
main(int argc, char **argv){
    int i = 0, num, size = 0, n = INITIAL_SIZE;
    int *A;

    A = malloc(n * sizeof(int));

    if(A == NULL){
        printf("OUT OF MEMORY\n");
        exit(EXIT_FAILURE);
    }

    while(scanf("%d",&num) == 1 && getchar()!='\n'){
        A[i] = num;
        i++;
        size++;
        if (size >= n){
            n = n * 2;
            A = realloc(A,n * sizeof(int));
        }
    }

    printf("Int Array: ");
    for (i = 0; i <= size; i++){
        printf("%d ", A[i]);
    }
    printf("\n");

    return 0;
}

1 个解决方案

#1

There is nothing wrong with the realloc. You are printing an extra uninitialized index in the last loop. Fix it by changing

realloc没有任何问题。您正在最后一个循环中打印一个额外的未初始化索引。通过改变来修复它

for (i = 0; i <= size; i++)

for (i = 0; i < size; i++)

The only problem with the realloc is that you don't check if it was successful just like you did for the malloc. Another problem is that you don't free the allocated memory.

realloc的唯一问题是你不会像对malloc一样检查它是否成功。另一个问题是你没有释放分配的内存。

#1